Strain gauges · Measurement

Transverse sensitivity: correction for two perpendicular gauges

Correct the indicated strains of two perpendicular strain gauges for transverse sensitivity q and report the error without correction.

DMSKeil 2017
01

Inputs

Valid for two exactly perpendicular gauges with equal q. For three-element rosettes apply the equations pairwise; q itself varies with temperature and production lot.

02

Results

Enter values and run the calculation.

Method

What is calculated?

A gauge also responds to strain transverse to its measuring direction; the ratio of sensitivities is the transverse sensitivity q (Keil eq. 2.16). Because the manufacturer calibrates k on a beam with ν₀ = 0.285, the gauge only reads without error in exactly that uniaxial field. For two perpendicular gauges, eq. 2.25 can be solved for both true strains.

Equations

ε′ = (εₗ + q·εq)/(1 − ν₀·q) (Keil Gl. 2.25)

εₐ = (1 − ν₀q)(ε′ₐ − q·ε′ᵦ)/(1 − q²)

εᵦ = (1 − ν₀q)(ε′ᵦ − q·ε′ₐ)/(1 − q²)

f = q(ν₀ + εq/εₗ)/(1 − qν₀) (Keil Gl. 2.26)

Procedure

Step by step

  1. Record both indicated strains with the same gauge factor set on the amplifier.
  2. Take q and ν₀ from the gauge manufacturer's datasheet.
  3. Use the corrected strains for stress calculation and the error values to judge whether the correction matters.

Typical mistake

Using the percentage value of q as an absolute number, or ignoring the sign of q (can be negative for long grids).

Practice

Application and limits

Stress analysis with T rosettes or two single gauges, especially when one gauge lies transverse to the principal strain: Keil's example with q = 1 % and εq/εₗ = −3.33 gives an error of −3.1 %.

Valid for two exactly perpendicular gauges with equal q. For three-element rosettes apply the equations pairwise; q itself varies with temperature and production lot.

Source

Technical basis

Keil, Dehnungsmessstreifen, 2nd ed. 2017, sec. 2.3 transverse sensitivity, eqs. (2.16), (2.20)–(2.27).

The source supports the equation structure and worked examples; this calculator does not replace calibration of the measuring chain.

FAQ

Frequently asked questions

When can I skip the correction?

In uniaxial loading along the gauge with ν ≈ 0.285 the error is zero; Keil's rule of thumb 2.27 gives f ≈ q·εq/εₗ.

Why does ν₀ = 0.285 appear?

Because the transverse component present during calibration is already contained in the stated gauge factor (eq. 2.23).

Does it apply to 45° rosette grids?

For the 45° grid the transverse strain must be derived from the other two grids; the correction is then done iteratively or with the manufacturer's rosette formulas.