MethodWhat is calculated?
With equal nominal resistances in all arms, eq. 4.1 yields the basic equation 4.6. Its numerator shows the sign rule: strains in arms 1 and 3 count positive, in 2 and 4 negative. The denominator carries the sum of all resistance changes – if non-zero the bridge becomes non-linear, which matters most with a single active arm.
Equations
U_M/U_B = (ΔR₁−ΔR₂+ΔR₃−ΔR₄) / (2(2R₀+ΔR₁+ΔR₂+ΔR₃+ΔR₄)) (Keil Gl. 4.6)
U_M/U_B ≈ k/4·(ε₁ − ε₂ + ε₃ − ε₄) (linearisiert, Keil Gl. 4.10 ff.)
ΔRᵢ/R₀ = k·εᵢ
ProcedureStep by step
- Assign each arm its strain (fixed resistors and compensation gauges: 0).
- Enter gauge factor and excitation.
- Compare linearised and exact signals; for large strains evaluate with the exact value.
Typical mistake
Entering compensation gauges with their temperature apparent strain although it is equal in all arms and cancels – or forgetting the sign of compression.
PracticeApplication and limits
Designing transducer circuits, checking temperature compensation (equal strain in all arms gives zero) and assessing quarter-bridge non-linearity on plastics or in the elasto-plastic range.
Equal nominal resistances and gauge factors in all arms, constant-voltage excitation, unloaded output.
SourceTechnical basis
Keil, Dehnungsmessstreifen, 2nd ed. 2017, sec. 4.2, eqs. (4.2)–(4.8); sec. 4.5, eqs. (4.10)–(4.18).
The source supports the equation structure and worked examples; this calculator does not replace calibration of the measuring chain.
FAQFrequently asked questions
How large is the quarter-bridge linearity error?
Per Keil about equal to the strain: around 0.1 % at 1000 µm/m.
Why is the full bridge with ±ε linear?
Because the resistance changes in the denominator sum to zero.
Can I account for unequal gauge factors?
Approximately, by scaling an arm's strain with kᵢ/k.
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