MethodWhat is calculated?
With equal nominal resistances in all arms, eq. 4.1 yields the basic equation 4.6. Its numerator shows the sign rule: strains in arms 1 and 3 count positive, in 2 and 4 negative. The denominator carries the sum of all resistance changes – if non-zero the bridge becomes non-linear, which matters most with a single active arm.
Equations
U_M/U_B = (ΔR₁−ΔR₂+ΔR₃−ΔR₄) / (2(2R₀+ΔR₁+ΔR₂+ΔR₃+ΔR₄)) (Keil Gl. 4.6)
U_M/U_B ≈ k/4·(ε₁ − ε₂ + ε₃ − ε₄) (linearisiert, Keil Gl. 4.10 ff.)
ΔRᵢ/R₀ = k·εᵢ
LimitsAssumptions and typical mistake
Equal nominal resistances and gauge factors in all arms, constant-voltage excitation, unloaded output.
Entering compensation gauges with their temperature apparent strain although it is equal in all arms and cancels – or forgetting the sign of compression.
InputsWhat you enter – and where the values come from
- Gauge factor k
- The gauge factor is the sensitivity of the strain gauge: it states how much the electrical resistance changes when the gauge is stretched (ΔR/R = k·ε). Without it no strain can be computed from an electrical signal. Source: printed on every gauge package or in the manufacturer datasheet, typically 2.0 to 2.1 for constantan foil gauges; valid at room temperature. The same value must be set in the amplifier.
- Strain ε₁ [µm/m]
- Strain under the gauge in bridge arm 1. Enter 0 for a fixed resistor or an unloaded compensation gauge. Strains in arms 1 and 3 enter the signal positively. Source: expected strain from calculation or measurement; mind the sign (compression negative).
- Strain ε₂ [µm/m]
- Strain in arm 2, adjacent to arm 1; strains here are subtracted from the signal. That is why a compensation gauge (temperature only) belongs here, and for bending the gauge on the opposite side so the magnitudes add.
- Strain ε₃ [µm/m]
- Strain under the gauge in arm 3, diagonally opposite arm 1. Strains here add to those of arm 1 – which is why in full bridges the two equally loaded gauges sit in arms 1 and 3. Enter 0 for a fixed resistor or compensation gauge.
- Strain ε₄ [µm/m]
- Strain under the gauge in arm 4, adjacent to arms 1 and 3; like arm 2 it is subtracted from the signal. In a bending full bridge the second compression-side gauge sits here so the magnitudes add. Enter 0 for a fixed resistor or compensation gauge.
- Excitation U_B [V]
- The bridge excitation is the DC or AC voltage with which the amplifier supplies the bridge circuit. The signal is proportional to it – which is why signals are usually stated as a ratio in mV/V and the excitation is only needed for the absolute signal voltage. Source: amplifier setting, usually 2.5 V, 5 V or 10 V; the upper limit is set by gauge self-heating (see the excitation calculator).
ContextWhat this calculator is for
Designing transducer circuits, checking temperature compensation (equal strain in all arms gives zero) and assessing quarter-bridge non-linearity on plastics or in the elasto-plastic range.
What comes next
- Assign each arm its strain (fixed resistors and compensation gauges: 0).
- Enter gauge factor and excitation.
- Compare linearised and exact signals; for large strains evaluate with the exact value.
SourceTechnical basis
Keil, Dehnungsmessstreifen, 2nd ed. 2017, sec. 4.2, eqs. (4.2)–(4.8); sec. 4.5, eqs. (4.10)–(4.18).
The source supports the equation structure and worked examples; this calculator does not replace calibration of the measuring chain.
FAQFrequently asked questions
How large is the quarter-bridge linearity error?
Per Keil about equal to the strain: around 0.1 % at 1000 µm/m.
Why is the full bridge with ±ε linear?
Because the resistance changes in the denominator sum to zero.
Can I account for unequal gauge factors?
Approximately, by scaling an arm's strain with kᵢ/k.
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