Strain gauges · Measurement

Basic strain-gauge bridge equation: signal from four strains

Calculate the bridge output from the strains in the four arms and the gauge factor – linearised and with the exact equation 4.6.

DMSKeil 2017
01

Inputs

Equal nominal resistances and gauge factors in all arms, constant-voltage excitation, unloaded output.

02

Results

Enter values and run the calculation.

Method

What is calculated?

With equal nominal resistances in all arms, eq. 4.1 yields the basic equation 4.6. Its numerator shows the sign rule: strains in arms 1 and 3 count positive, in 2 and 4 negative. The denominator carries the sum of all resistance changes – if non-zero the bridge becomes non-linear, which matters most with a single active arm.

Equations

U_M/U_B = (ΔR₁−ΔR₂+ΔR₃−ΔR₄) / (2(2R₀+ΔR₁+ΔR₂+ΔR₃+ΔR₄)) (Keil Gl. 4.6)

U_M/U_B ≈ k/4·(ε₁ − ε₂ + ε₃ − ε₄) (linearisiert, Keil Gl. 4.10 ff.)

ΔRᵢ/R₀ = k·εᵢ

Procedure

Step by step

  1. Assign each arm its strain (fixed resistors and compensation gauges: 0).
  2. Enter gauge factor and excitation.
  3. Compare linearised and exact signals; for large strains evaluate with the exact value.

Typical mistake

Entering compensation gauges with their temperature apparent strain although it is equal in all arms and cancels – or forgetting the sign of compression.

Practice

Application and limits

Designing transducer circuits, checking temperature compensation (equal strain in all arms gives zero) and assessing quarter-bridge non-linearity on plastics or in the elasto-plastic range.

Equal nominal resistances and gauge factors in all arms, constant-voltage excitation, unloaded output.

Source

Technical basis

Keil, Dehnungsmessstreifen, 2nd ed. 2017, sec. 4.2, eqs. (4.2)–(4.8); sec. 4.5, eqs. (4.10)–(4.18).

The source supports the equation structure and worked examples; this calculator does not replace calibration of the measuring chain.

FAQ

Frequently asked questions

How large is the quarter-bridge linearity error?

Per Keil about equal to the strain: around 0.1 % at 1000 µm/m.

Why is the full bridge with ±ε linear?

Because the resistance changes in the denominator sum to zero.

Can I account for unequal gauge factors?

Approximately, by scaling an arm's strain with kᵢ/k.