Strain gauges · Measurement

Wheatstone bridge: output voltage of the unbalanced bridge

Calculate the bridge output voltage and ratio U_M/U_B exactly from the four arm resistances and the excitation.

DMSKeil 2017
01

Inputs

Constant-voltage excitation and an unloaded measuring diagonal (high-impedance amplifier input). Constant-current excitation or a low-impedance load require different relations.

02

Results

Enter values and run the calculation.

Method

What is calculated?

The bridge is two voltage dividers on the same excitation; the output is the difference of the two divider voltages. Hence equal-sign resistance changes in adjacent arms cancel while those in opposite arms add. For small changes eq. 4.1 reduces to the linearised basic equation 4.6.

Equations

U_M/U_B = R₁/(R₁+R₂) − R₄/(R₃+R₄) (Keil Gl. 4.1)

Abgleich: R₁/R₂ = R₃/R₄

R_in = (R₁+R₂)‖(R₃+R₄)

Procedure

Step by step

  1. Enter all four arm resistances including lead contributions.
  2. Enter the excitation and read the output voltage.
  3. Vary one resistance to reproduce balance or a defined unbalance.

Typical mistake

Assigning the arms incorrectly: R₂ and R₄ are adjacent to R₁, R₃ is opposite; swapping flips the sign.

Practice

Application and limits

Checking zero errors caused by resistance tolerances, sizing balancing resistors and verifying the signal a resistance standard produces in one arm.

Constant-voltage excitation and an unloaded measuring diagonal (high-impedance amplifier input). Constant-current excitation or a low-impedance load require different relations.

Source

Technical basis

Keil, Dehnungsmessstreifen, 2nd ed. 2017, secs. 4.1–4.2, eqs. (4.1)–(4.6).

The source supports the equation structure and worked examples; this calculator does not replace calibration of the measuring chain.

FAQ

Frequently asked questions

How does this differ from the balanced-bridge calculator?

There an unknown resistance is found from balance; here the output of the deliberately unbalanced bridge is computed, as used in strain-gauge measurement.

Why is the signal given in mV/V?

Because U_M is proportional to U_B; the ratio characterises the bridge independently of the excitation.

Is the output linear in ΔR?

Only approximately; with one active arm eq. 4.7 gives an error equal in size to the strain itself.