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Engineering mechanics: statics, strength and motion

Calculate forces, stresses, deformations, motion, vibrations and hydrostatics with transparent models.

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Workflow

Choose the relevant topic and load model, enter quantities with units, then check the result and model limits.

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Calculators in this category

Statics and beam loads

Combine forces, replace distributed loads and find internal bending moments.

01Kosinussatz am Kräftedreieck · R = √(F₁² + F₂² + 2·F₁·F₂·cos α)

Resultant of two forces with an included angle

Calculate the magnitude of the resultant of two forces with a common point of application from both force magnitudes and their included angle using the cosine rule: R = √(F₁²+F₂²+2F₁F₂cos α). Solvable for each individual force and for the included angle.

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02Sinussatz am Kräftedreieck des Knotens · S₁ = G·sin α₂/sin(α₁+α₂)

Bar forces in a two-bar system (bracket, tripod)

Calculate the bar force in a two-bar system (bracket, jib, tripod) from the suspended load and the two bar angles to the load direction: S₁ = G·sin α₂/sin(α₁+α₂). Solvable for the load, so a limiting bar force yields the maximum load that may be suspended.

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03Resultierende einer linear verlaufenden Streckenlast · R = (q₁+q₂)/2 · l

Resultant of a trapezoidal or triangular line load

Calculate the resultant (total force) of a linearly varying line load from its two edge ordinates and the loaded length: R = (q₁+q₂)/2 · l. One formula covers rectangular, triangular and trapezoidal loads, and it is solvable for every input.

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04Wirkungslinie der Resultierenden einer linearen Streckenlast · xs = l/3 · (q₁+2q₂)/(q₁+q₂)

Position of the resultant of a trapezoidal or triangular line load

Calculate the distance of the resultant from the start of a linearly varying line load: xs = l/3 · (q₁+2q₂)/(q₁+q₂). This line of action is needed for the moment equilibrium – only for a uniform load does it lie at mid-length, whereas for a triangular load it sits at two thirds of the length.

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05Teilflächenverfahren · xs = (A₁·x₁ + A₂·x₂)/(A₁ + A₂)

Centroid from two part areas (composite method)

Calculate the centroid of an area composed of two parts with the composite method: xs = (A₁x₁ + A₂x₂)/(A₁+A₂). Cut-outs and holes are entered as a negative part area. The same works for masses if masses are entered instead of areas.

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06Einfach gelagerter Balken mit Einzellast · Mmax = F a(L−a)/L

Maximum beam moment under an off-centre point load

Calculate maximum bending moment of a simply supported beam under one off-centre point force from load, span and force location.

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Strength and deformation

Assess buckling limits, material properties, stresses and elastic deformation.

07Eulersche Knicktheorie · Fkrit = π²·E·I/lk²

Euler buckling load of a compression member

Calculate the critical buckling load Fkrit of a slender compression member from elastic modulus, smallest second moment of area and buckling length: Fkrit = π²EI/lk². The buckling length lk covers all four Euler cases through its factor, and any of the four quantities can be the target.

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08Schlankheitsgrad · λ = lk/i mit dem Trägheitsradius i = √(I/A)

Slenderness ratio and radius of gyration of a compression member

Calculate the slenderness ratio λ = lk/i of a compression member from buckling length, second moment of area and cross-sectional area; the radius of gyration i = √(I/A) is determined along the way. λ decides whether a member buckles elastically according to Euler or must be treated as a stocky member.

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09Euler-Hyperbel · σkrit = π²·E/λ²

Euler buckling stress of a compression member

Calculate the critical buckling stress σkrit = π²E/λ² of a compression member from elastic modulus and slenderness ratio. Comparing σkrit with the material's proportional limit shows immediately whether the Euler formula is valid for the member at all.

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10Gültigkeitsgrenze der Euler-Formel · λ₀ = π·√(E/|σP|)

Limit slenderness: validity boundary of the Euler formula

Calculate the limit slenderness λ₀ = π·√(E/|σP|) from elastic modulus and proportional limit. λ₀ separates slender members that buckle elastically according to Euler from stocky members for which the Euler formula is inadmissible – for structural steel S235 it gives λ₀ ≈ 104.

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11Isotropes Elastizitätsgesetz · G = E/(2·(1+ν))

Shear modulus from Young's modulus and Poisson's ratio

Calculate the shear modulus G = E/(2·(1+ν)) from Young's modulus and Poisson's ratio – also rearranged for E or ν. An isotropic elastic material has only two independent elastic constants, so the third always follows from the other two.

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12Querkontraktion · εq = −ν·εl und Δd = εq·d₀

Transverse contraction: lateral strain and diameter change

Calculate the lateral strain εq = −ν·εl and the resulting diameter or width change Δd of a loaded bar. Solvable for Poisson's ratio ν, so that ν can be determined directly from measured longitudinal and transverse deformation in a tensile test.

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13Kesselformel · σφ = p·r/t (Umfangsspannung) und σx = p·r/(2t) (Längsspannung)

Boiler formula: hoop stress in a thin-walled cylinder

Calculate the hoop stress (circumferential stress) σφ = p·r/t of a thin-walled cylindrical vessel or pipe under internal pressure – solvable for pressure, radius and wall thickness. Hoop stress is twice the longitudinal stress σx = p·r/(2t), which is why pipes and vessels under internal pressure split lengthwise.

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14Lamé-Spannungsverteilung bei reinem Innendruck · σt(ri) = pi(ra²+ri²)/(ra²−ri²)

Hoop stress in a thick-walled cylinder

Calculate hoop stress at the inner wall of a thick cylindrical tube under internal pressure from pressure and inner and outer radii.

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15Spannung im Mittelpunkt einer freien rotierenden Vollscheibe · σ0 = (3+ν)ρω²R²/8

Stress at the centre of a rotating solid disk

Calculate the maximum radial and hoop stress of a free rotating solid disk of constant thickness from density, rotational speed, radius and Poisson ratio.

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16Euler-Bernoulli-Biegelinie bei Endkraft · θ = FL²/(2EI)

Cantilever tip rotation under an end load

Calculate the slope angle at the free end of a cantilever beam from end force, length, Young modulus and second moment of area.

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17Integrierte Eigengewichtsdehnung · ΔL = ρgL²/(2E)

Extension of a hanging rod under its own weight

Calculate elongation of a uniform vertical rod fixed at its top due solely to self-weight from density, length, Young modulus and gravity.

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Motion, kinetics and impact

Calculate trajectories, rolling and sliding motion, and momentum and angular-momentum balances.

18Wurfparabel · w = v₀²/(2g)·sin 2α + √[v₀⁴/(4g²)·sin²2α + 2h·v₀²/g·cos²α]

Oblique projectile motion: range at any launch angle

Calculate the range of an oblique projectile from launch speed, launch angle and launch height – and conversely the launch speed needed for a required range. Unlike horizontal projectile motion the launch angle is free, and when launching above the landing point the optimum angle is below 45°.

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19Impulserhaltung und Stoßzahl · m₁v₁+m₂v₂ = m₁v₁'+m₂v₂' mit k = (v₂'−v₁')/(v₁−v₂)

Straight central impact: velocity after impact

Calculate the velocity of a body after a straight central impact from both masses, both velocities before impact and the coefficient of restitution k. Through k one calculator covers every case: k = 0 perfectly plastic, k = 1 perfectly elastic, in between the real impact. Solvable for k to determine the coefficient of restitution from a measured velocity.

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20Energieverlust beim geraden zentrischen Stoß · ΔT = ½·(1−k²)·m₁m₂/(m₁+m₂)·(v₁−v₂)²

Kinetic energy loss in a straight central impact

Calculate the loss of kinetic energy in a straight central impact from both masses, both velocities before impact and the coefficient of restitution: ΔT = ½(1−k²)·m₁m₂/(m₁+m₂)·(v₁−v₂)². This energy goes into deformation, heat and sound – in hammering and pile driving it is precisely the useful part.

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21Steinerscher Satz · JA = JS + m·rS²

Parallel-axis theorem: mass moment of inertia about a parallel axis

Calculate the mass moment of inertia of a body about any axis from its value about the parallel axis through the centre of mass: JA = JS + m·rS². Solvable for the centroidal inertia, the mass and the axis distance, so a measured value can also be reduced back to the centroidal one.

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22Kreiselmoment bei senkrechten Drehachsen · MK = J · ωK · ωF

Gyroscopic moment: bearing load from a guided rotor

Calculate the gyroscopic moment MK = J·ωK·ωF that the bearings of a rotating body must additionally carry when its axis of rotation is itself being swivelled. This simplified form holds for mutually perpendicular axes of rotation – the usual case in machine dynamics.

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23Schlupffreies Rollen auf der schiefen Ebene · a = g·sin α/(1 + JS/(m·R²))

Rolling acceleration of a body on an inclined plane

Calculate the acceleration of a body rolling without slip down an inclined plane from the slope angle and the inertia ratio: a = g·sin α/(1 + JS/(m·R²)). A solid cylinder reaches two thirds, a sphere five sevenths and a thin-walled tube only half the acceleration of a sliding body.

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24Drehimpulserhaltung · J₁ω₁ + J₂ω₂ = (J₁+J₂)·ω

Common speed after two rotating masses are coupled

Calculate the common speed of two rotating masses after they are coupled, from both inertias and both initial speeds: ω = (J₁ω₁ + J₂ω₂)/(J₁+J₂). Angular momentum is conserved, rotational energy is not – the difference is converted into heat as friction work in the clutch.

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25Energiesatz mit Reibarbeit · v = √(2·L·g·(sin α − μ·cos α))

Exit speed on an inclined slide with friction

Calculate the exit speed of a sliding body at the end of an inclined slide from the slide length, the slope angle and the kinetic friction coefficient using the energy principle: v = √(2·L·g·(sin α − μ·cos α)). Mass and material cancel out – only geometry and the friction coefficient matter.

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Vibrations

Assess natural periods and transmission of oscillating forces.

Hydrostatics

Determine pressure forces in still liquids and initial stability of floating bodies.