MethodWhat is calculated?
The amplifier displays the bridge voltage ratio. Gauge factor and bridge factor turn it into strain; for the quarter bridge the exact eq. 4.7 yields a slightly larger strain than the linear approximation at large signals. Converting to stress is valid only for a uniaxial stress state – biaxial states need two strains and Hooke's law per eqs. 9.27/9.28.
Equations
ε = 4·(U_M/U_B)/(k·B) (aus Keil Gl. 4.8)
Viertelbrücke exakt: U_M/U_B = ΔR/(2(2R₀+ΔR)) ⇒ ΔR/R₀ = 4s/(1−2s) (Keil Gl. 4.7)
σ = E·ε (einachsig)
LimitsAssumptions and typical mistake
Lead resistance, transverse sensitivity and temperature response are excluded; the non-linearity correction applies to one active arm only (B = 1).
Using the amplifier's fixed gauge factor 2.00 although the gauge has 2.08, or entering the signal in mV instead of mV/V.
InputsWhat you enter – and where the values come from
- Bridge signal U_M/U_B [mV/V]
- The bridge signal is what the amplifier delivers as raw value: the Wheatstone bridge output divided by the excitation, in millivolts per volt. A typical strain-gauge transducer delivers 1 to 2 mV/V at rated load; 1000 µm/m on a single gauge with k = 2 give 0.5 mV/V. Source: amplifier reading in mV/V mode after zero balancing, or a transducer test certificate.
- Gauge factor k
- The gauge factor is the sensitivity of the strain gauge: it states how much the electrical resistance changes when the gauge is stretched (ΔR/R = k·ε). Without it no strain can be computed from an electrical signal. Source: printed on every gauge package or in the manufacturer datasheet, typically 2.0 to 2.1 for constantan foil gauges; valid at room temperature. The same value must be set in the amplifier.
- Bridge factor B
- The bridge factor states how many times the strain of a single gauge is contained in the signal – it depends only on the wiring: 1 for a single gauge (quarter bridge), 2 for two gauges top/bottom in bending, 4 for four gauges in bending or torsion, 2(1+ν) ≈ 2.6 for two longitudinal and two transverse gauges on a tension rod. Source: read from your own wiring or determine with the ‘quarter, half and full bridge’ calculator. Note: if B is already set in the amplifier it displays strain directly – then enter 1 here.
- Young's modulus E [N/mm²]
- Young's modulus describes how stiff the part's material is – how much stress it takes to produce a given strain (σ = E·ε). It is needed to turn measured or computed strains into stresses and vice versa. Source: material tables or datasheet; steel ≈ 210 000 N/mm², aluminium ≈ 70 000 N/mm², titanium ≈ 110 000 N/mm². E drops at elevated temperature.
ContextWhat this calculator is for
Evaluating raw signals from data loggers without a strain-gauge mode, converting transducer sensitivities and checking amplifier settings (gauge factor, bridge factor).
What comes next
- Enter the signal in mV/V, gauge factor and bridge factor of the circuit used.
- For quarter bridges above 1 mV/V use the exact value.
- Adopt σ = E·ε only for uniaxial loading along the gauge.
SourceTechnical basis
Keil, Dehnungsmessstreifen, 2nd ed. 2017, sec. 4.2, eqs. (4.7), (4.8), fig. 4.2; sec. 9.4, eqs. (9.27), (9.28).
The source supports the equation structure and worked examples; this calculator does not replace calibration of the measuring chain.
FAQFrequently asked questions
How large is the non-linearity at 0.5 mV/V?
ΔR/R₀ = 4·0.0005/(1−0.001) = 2.002 ‰ instead of 2.000 ‰, i.e. 0.1 %.
What if the amplifier reads µm/m?
Then it has already applied its gauge and bridge factors; only deviations need correcting (ε = ε_reading·k_instrument/k_gauge).
Can I compute σ this way for bending?
Yes, the outer-fibre stress is uniaxial; ε must be the bending strain of one gauge, not B times it.
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