What does shaft pre-sizing calculate?
The calculator finds the smallest diameter of a smooth solid shaft for which the equivalent stress from bending and torsion does not exceed Re/S. Bending moment produces normal stress sigma_b = 32·Mb/(pi·d^3), while torque produces shear stress tau_t = 16·Mt/(pi·d^3). For ductile shaft steel, the distortion-energy criterion combines them as sigma_v = sqrt(sigma_b^2 + 3 tau_t^2).
How to use the calculator
Enter bending and torsional moment at the critical section, the shaft material's yield strength and the required safety factor. The calculator iterates to find the minimum diameter of a smooth solid shaft.
Worked example
A safety factor of 2 halves allowable stress and noticeably increases required diameter compared with factor 1.
How to read minimum diameter and stresses
Minimum diameter is a calculated boundary for the entered load case. Round up to an available diameter for design, then verify the real geometry. Separate bending and torsional stresses show which load component dominates; equivalent stress is their common assessment quantity. At 100% utilization Re/S is fully used, but notch, fatigue and stiffness checks are still absent.
Moments in N·m, yield strength in MPa, diameter in millimetres.
Typical applications
A quick first estimate of shaft diameter in an early design phase, before geometry details such as shoulders and keyways are fixed.
Assumptions, limits and common mistakes
Classical elasticity and DIN 743 preliminary design; notches, keyways and fatigue need the complete verification.
Common mistake: Do not take this value as a final manufacturing diameter – it applies to a smooth, notch-free shaft. Shoulders, keyways, holes and fillets noticeably raise local stress and require the complete DIN 743 strength verification with notch effect, size and surface influence and separate fatigue and static safety.
Frequently asked questions
Why isn't this pre-sizing enough as a final verification?
It addresses only the static limit case of a smooth shaft. Notch effects, fatigue strength, load variation and real shaft shoulders are only captured by the complete DIN 743 verification.
How strongly does safety factor affect diameter?
Since stress falls with the cube of diameter, a higher required safety factor produces a disproportionately larger required diameter.
Why aren't bending and torsion simply added?
They produce different stress types (normal and shear); only an equivalent-stress hypothesis such as von Mises combines them correctly into a single equivalent stress.
Which bending moment and torque should I enter?
Use the internal moments acting simultaneously at the likely critical section in the governing load case. Do not combine maxima from separate load cases that can never occur together without justification.
Why must the calculated diameter be rounded up?
dmin is the exact mathematical boundary of the idealized model. Rounding down would exceed allowable equivalent stress; round up to an available stock or finished size with machining and verification margin.