Rtotal = R1 + R2 + R3
In series, individual resistances add and the same current flows through each part.
In series, individual resistances add and the same current flows through each part.
Select a target and calculate.
In series, individual resistances add and the same current flows through each part.
10 Ω + 15 Ω + 5 Ω = 30 Ω.
Ideal ohmic resistors without temperature coefficient.
This calculator finds the total resistance of a series connection of up to three resistors, or solves for a missing individual resistor. It explains why the same current flows through every resistor in a series circuit — and why, on old Christmas tree light strings, a single burned-out bulb could darken the entire string.
In a series connection, individual resistances add to give the total resistance: Rtotal = R1 + R2 + R3. The same current flows through every resistor, while total voltage divides across the individual resistors.
Old Christmas tree light strings were wired in series: every bulb sat on the same current path. If a single bulb's filament broke, the current path was interrupted and the whole string went dark — a vivid example of a series connection only working as a whole. Modern light strings avoid this with a bypass circuit built into each bulb.
Rtotal = R1 + R2 + R3
Rtotal = R1 + R2 + R3R3 = Rtotal − R1 − R2| Symbol / input | Meaning |
|---|---|
| Total resistance Rtotal | The equivalent resistance the whole series chain presents from outside – as a result the sum of all individual resistances. The same current flows through every component. |
| Resistance R1 | The first resistor in the series chain. Source: printed value/colour code on the part, or measured with an ohmmeter. |
| Resistance R2 | The second resistor in the series chain. |
| Resistance R3 | An optional third resistor; enter 0 if only two resistors are in series. |
Enter the known individual resistances; a value of 0 Ω for R3 means only two resistors are in series. The calculator adds the values to the total resistance or solves for a missing individual resistor.
Enter the known resistors and read off the total resistance, or enter the total resistance and known individual resistors to find the missing one.
Given R1 = 10 Ω, R2 = 15 Ω and R3 = 5 Ω, substitution gives Rtotal = 10 + 15 + 5 = 30 Ω.
A total resistance of 30 Ω means the series connection allows the same current at a given voltage as a single 30 Ω resistor. Since the same current flows through all three resistors, total voltage divides proportionally to the individual resistances — the largest resistor takes the largest voltage share.
Resistance is given in ohms (Ω), larger values in kΩ or MΩ. Rtotal = R1+R2+R3 holds regardless of unit choice, as long as all values are converted consistently.
Series connections are used for LED series resistors, simple voltage-divider chains, current limiting in test circuits, and in older light-string and heating-element designs.
The formula applies to ideal, linear resistors. For components with tolerances, temperature dependence, or nonlinear behaviour (e.g. incandescent filaments, whose resistance rises with temperature), the real total resistance deviates from the simple sum.
Common mistake: Do not confuse series with parallel connection: in series, resistances add directly; in parallel, their reciprocals add instead. Also, always assume the same current through every resistor in a series connection, not the same voltage.
Current. Voltage instead divides proportionally to the individual resistances across the components.
Because the bulbs were wired in series and a broken filament interrupted the single current path. Modern light strings use a bypass circuit so individual failures don't switch off the rest.
It simply adds to the existing total; the formula extends with any number of additional terms.