R1 = R0·[1+α·(T1−T0)]

Temperature dependence of a metallic resistor

Pure metals have a positive temperature coefficient; resistance rises approximately linearly with temperature.

MINTSI
01

Inputs

Resistance after the temperature change to T1.

Known resistance at the reference temperature T0.

Temperature at which R0 was measured or specified.

Temperature at which resistance R1 is required.

Material constant referenced to T0; copper ≈ 0.00393/K, aluminum ≈ 0.0040/K, constantan ≈ 0.00001/K.

02

Result

Select a target and calculate.

Calculation

R1 = R0 · [1 + α · (T1 − T0)]

Pure metals have a positive temperature coefficient; resistance rises approximately linearly with temperature.

Understand the inputs
  • Resistance at T1 R1Resistance after the temperature change to T1.
  • Resistance at T0 R0Known resistance at the reference temperature T0.
  • Reference temperature T0Temperature at which R0 was measured or specified.
  • Target temperature T1Temperature at which resistance R1 is required.
  • Temperature coefficient αMaterial constant referenced to T0; copper ≈ 0.00393/K, aluminum ≈ 0.0040/K, constantan ≈ 0.00001/K.
Example

100 Ω at 20 °C with α = 0.00393/K, heated to 80 °C: R1 = 100 Ω · [1 + 0.00393 · 60] = 123.58 Ω, i.e. +23.6%.

Assumptions and limits

Linear approximation about the reference temperature T0 for pure metals; does not apply to NTC or PTC thermistors with strongly nonlinear behavior.

Technical article

Understand Temperature dependence of a metallic resistor

This calculator finds how much a metallic conductor's resistance changes for a given temperature change, starting from a known resistance at a reference temperature and the material's linear temperature coefficient.

What does this quantity describe?

For pure metals, resistivity rises approximately linearly with temperature. Given resistance R0 at reference temperature T0, resistance R1 at another temperature T1 follows from R1 = R0·[1 + α·(T1 − T0)], where α is the material's temperature coefficient.

This works similarly to the thermal expansion of a metal bar: both effects are a good linear approximation for small to moderate temperature changes and are described by a material-specific constant — except here it is electrical resistance rather than length that is affected, because stronger lattice vibrations at higher temperature impede electron motion more.

Formula and variables

R1 = R0 · [1 + α · (T1 − T0)]

  • R1 = R0·[1 + α·(T1 − T0)]
  • α = (R1/R0 − 1)/(T1 − T0)
  • T1 = T0 + (R1/R0 − 1)/α
Symbol / inputMeaning
Resistance at T1 R1Resistance after the temperature change to T1.
Resistance at T0 R0Known resistance at the reference temperature T0.
Reference temperature T0Temperature at which R0 was measured or specified.
Target temperature T1Temperature at which resistance R1 is required.
Temperature coefficient αMaterial constant referenced to T0; copper ≈ 0.00393/K, aluminum ≈ 0.0040/K, constantan ≈ 0.00001/K.

Choose the inputs correctly

R0, T0, T1 and temperature coefficient α determine R1. α is a material property referenced to a specific temperature, usually 20 °C, and is assumed constant over the temperature range considered.

How to use the calculator

Select the target quantity. For resistance at the target temperature, enter R0, T0, T1 and α. To find a measured temperature coefficient instead, choose α as the target and enter two measured resistances with their temperatures.

Worked example

A 100 Ω copper resistor at 20 °C with α = 0.00393/K, heated to 80 °C: R1 = 100 Ω · [1 + 0.00393 · 60] = 123.58 Ω, an increase of 23.58 Ω or +23.6%.

Understand the result and units

A 23.6% resistance increase for a 60 K rise shows why metallic winding resistances and heating elements have noticeably higher resistance at operating temperature than at room temperature — an effect resistance thermometers (Pt100) deliberately exploit for temperature measurement.

R0 and R1 are given in Ω, T0 and T1 in °C, and α in 1/K, equivalent to 1/°C for temperature differences.

Why doesn't this apply to NTC and PTC thermistors?

NTC thermistors are made from sintered polycrystalline mixed-oxide ceramic and show a pronounced but strongly nonlinear exponential decrease in resistance with rising temperature, typically 3 to 6% per kelvin. PTC thermistors, made from sintered metal oxides, show a step-like resistance increase of several orders of magnitude above a reference temperature. Both effects are nonlinear enough that the linear equation used here — valid for pure metals with a small, approximately constant α — cannot represent them; NTC and PTC components need their own characteristic-curve models from the specific component datasheet.

Typical applications

The relationship is used to correct cable and winding resistance to operating temperature, to design resistance thermometers, and to estimate motor and transformer winding heating from a resistance measurement taken before and after operation.

Assumptions, limits and common mistakes

The linear approximation works well for pure metals over moderate temperature ranges but increasingly deviates from the actual, slightly curved characteristic at very large temperature changes. For NTC and PTC thermistors — semiconductor ceramics with strongly nonlinear, exponential or step-like temperature-resistance behavior — this linear formula does not apply; they need their own material-specific characteristic models, such as the B-parameter equation for NTC thermistors.

Common mistake: A common mistake is applying this linear formula unchanged to NTC or PTC components, even though their resistance change is many times larger and nonlinear. It is also easy to overlook that α itself is slightly temperature-dependent, making the linear approximation less accurate for very large temperature swings well above 100 K.

Frequently asked questions

Why do pure metals have a positive temperature coefficient?

Because stronger lattice vibrations at higher temperature impede the free motion of conduction electrons more, raising resistance.

What is the difference to NTC and PTC thermistors?

NTC and PTC thermistors are semiconductor ceramics with strongly nonlinear, exponential or step-like behavior and need their own models; the linear formula used here applies only to pure metals.

What alpha values are typical?

Copper is about 0.00393/K, aluminum about 0.0040/K, while special copper-manganese alloys such as constantan or manganin have a very small coefficient of about 0.00001/K and are therefore used for precision resistors.

Why does the reference temperature T0 matter?

Because α itself is referenced to a specific temperature; if R0 is measured at a temperature other than the datasheet's stated reference, the result deviates slightly.

Can I use this formula for aluminum or other metals?

Yes, provided a suitable temperature coefficient α for that metal is used; the formula itself is material-independent, only the numeric value of α changes.