R = ρ · L / A; Vdrop = I · R
R = ρ·L/A; given a known current, the same resistance also yields voltage drop and ohmic power loss for cable sizing.
R = ρ·L/A; given a known current, the same resistance also yields voltage drop and ohmic power loss for cable sizing.
Select a target and calculate.
R = ρ·L/A; given a known current, the same resistance also yields voltage drop and ohmic power loss for cable sizing.
20 m of copper cable (ρ ≈ 0.0175 Ω·mm²/m) with a 1.5 mm² cross-section gives R ≈ 0.233 Ω; at 10 A this is a voltage drop of about 2.33 V (P = I²·R ≈ 23.3 W).
DC, homogeneous cross-section and constant temperature; contact resistance and high-frequency skin effect are excluded.
This calculator finds a conductor's DC resistance from resistivity, length and cross-section, and derives voltage drop and ohmic power loss at a known current — the key figures for cable sizing.
The resistance of a homogeneous conductor is proportional to its length L and the material's resistivity ρ, and inversely proportional to its cross-section A: R = ρ·L/A. At a known operating current I this gives the voltage drop Vdrop = I·R and the power dissipated as heat P = I²·R.
Picture the conductor as a narrow pipe carrying a viscous fluid: a long, thin pipe resists flow more than a short, thick one; the conductor material corresponds to how rough the pipe wall is.
R = ρ · L / A; Vdrop = I · R
R = ρ·L/AVdrop = I·RP = I²·R| Symbol / input | Meaning |
|---|---|
| Conductor resistance R | Ohmic resistance of the conductor at the reference temperature of ρ. |
| Resistivity ρ | Material property; copper about 0.0175 Ω·mm²/m at 20 °C, aluminum about 0.0282 Ω·mm²/m at 20 °C. |
| Conductor length L | Electrical length; add both go and return conductors where relevant. |
| Conductor area A | Metal cross-section normal to current flow. |
| Operating current I | Current used to compute voltage drop and power loss. |
| Voltage drop Vdrop | Ohmic voltage drop along the conductor at current I. |
Resistivity ρ, length L and area A give R; adding operating current I gives the voltage drop. ρ is a material property at a reference temperature, usually 20 °C; for other operating temperatures, the linked temperature-dependence calculator gives the correction.
Select the target quantity. For resistance, enter ρ, L and A. For cable sizing, choose area A as the target and work back from the allowable voltage drop via R = Vdrop/I, or use voltage drop Vdrop directly as the target to check the effect of an existing cross-section.
20 m of copper cable (ρ ≈ 0.0175 Ω·mm²/m at 20 °C) with a 1.5 mm² cross-section gives R = 0.0175 · 20 / 1.5 ≈ 0.233 Ω. At 10 A this is a voltage drop of 2.33 V and a power loss of P = I²·R ≈ 23.3 W.
A voltage drop of 2.33 V on a 230 V load is about 1% of the rated voltage, within typical tolerance limits for final circuits; the same 2.33 V on a 12 V low-voltage system would instead be nearly 20% and generally unacceptable.
Resistivity is often given in Ω·mm²/m, conveniently matching cable cross-sections in mm², less commonly in Ω·m; 1 Ω·mm²/m equals 10⁻⁶ Ω·m. Length is given in m, area in mm² and resistance in Ω.
This calculator extends the bare R = ρ·L/A formula with operating current as an input, to directly derive voltage drop and power loss — the practical figures that matter for cable sizing. If only the bare resistance without a current input is needed, the simpler conductor resistance calculator is sufficient.
The relationship is used to select cable cross-sections for long runs, to estimate transmission losses in wiring, and to size windings in coils and transformers, where winding resistance sets ohmic losses.
The model applies to DC at a constant temperature uniform across the conductor cross-section and excludes contact and transition resistance at terminals and connectors. At high-frequency AC, the skin effect pushes current toward the conductor's outer surface, so effective AC resistance exceeds the DC value computed here; at 50/60 Hz this effect is negligible for common conductor sizes.
Common mistake: A common mistake is entering only the one-way run length for a circuit with a return conductor instead of double that length, underestimating voltage drop and power loss by a factor of two. Resistivity is also sometimes used without regard to actual operating temperature, even though ρ for metals rises noticeably with temperature.
It is the resistance of a 1 m length with a 1 mm² cross-section of the given material; copper, at about 0.0175 Ω·mm²/m, is markedly lower than aluminum (about 0.0282 Ω·mm²/m) or steel.
Because resistance is proportional to length and inversely proportional to cross-section — a long path with little available cross-section area impedes current flow more.
This calculator uses the same core R = ρ·L/A but adds operating current, voltage drop and power loss — relevant when checking whether a cable cross-section suffices for an application.
Only partly: at high frequencies the skin effect concentrates current near the conductor's outer surface, so effective resistance exceeds the DC value computed here.
Compute the allowable resistance from R = Vdrop,max/I, set that as the target value for R and solve for A; or choose A directly as the target and adjust it until the shown voltage drop falls within the allowable range.