p = F / A
Small contact areas create high pressure for the same force.
Small contact areas create high pressure for the same force.
Select a target and calculate.
Small contact areas create high pressure for the same force.
1,000 N over 100 cm² gives 1 bar.
Uniformly distributed static normal load.
This calculator finds the missing quantity among pressure p, force F and area A from the other two. It shows why the same force can produce a vastly different pressure depending on the area it acts on, and explains the difference between gauge and absolute pressure.
Pressure is the force acting perpendicular to a surface, divided by the size of that surface: p = F/A. For the same force, a smaller area produces a higher pressure.
A person in stiletto heels and a person in flat, wide shoes can exert the same body weight, and therefore the same force, on the floor. Because a stiletto heel's contact area is far smaller than a flat sole, the pressure under the heel can be many times higher than under a wide shoe — in extreme cases even higher than under an elephant's foot.
p = F / A
p = F / AF = p · AA = F / p| Symbol / input | Meaning |
|---|---|
| Mean pressure p | The mean force per unit area, assumed uniformly distributed. For gases and liquids this usually means gauge pressure above atmospheric (a manometer reads gauge pressure), not absolute pressure – check the instrument or datasheet if unsure. |
| Normal force F | The force pressing or pulling perpendicular to area A. Source: a force measurement, a known weight (F = m·g), or as the result of p·A. |
| Effective area A | The area actually loaded by F – not the whole part's surface, only the contact or effective region. Source: calculate it from a drawing (e.g. circular area π·d²/4) or measure it directly. |
Enter two of the three quantities. Pressure requires force and area, force requires pressure and area, area requires force and pressure. For fluids especially, clarify whether the pressure in question is gauge pressure (relative to the atmosphere) or absolute pressure.
Select the target quantity and enter the two known values with units. For technical data, check whether a force acts perpendicular to the area or whether a force component must be resolved first.
Given F = 1,000 N and A = 100 cm² = 0.01 m², substitution gives p = 1,000 N / 0.01 m² = 100,000 Pa = 1 bar. If the same force acted on only 1 cm², the result would already be p = 100 bar.
A pressure of 1 bar (100,000 Pa) is roughly the average atmospheric pressure at sea level. The example shows that mechanical stress depends not on force alone but on the ratio of force to area — which is why wide foundations or skis spread a given force over a larger area to reduce pressure.
The SI unit is the pascal (Pa = N/m²). Engineering commonly uses bar, kPa, MPa and psi: 1 bar = 100,000 Pa = 100 kPa, and 1 MPa = 1 N/mm². One standard atmosphere (atm) equals 101,325 Pa.
Absolute pressure is measured relative to a vacuum (zero pressure). Gauge pressure is instead measured relative to the current atmospheric pressure and is what most technical pressure gauges display. Approximately, absolute pressure = gauge pressure + atmospheric pressure (about 1.013 bar at sea level). Calculations involving ideal gases or vacuum applications always require absolute pressure.
Pressure calculations are used to design foundations and bearing surfaces, hydraulic and pneumatic systems, tyre pressure specifications, and to estimate contact pressure in materials testing.
The formula gives an area-averaged pressure for a uniformly distributed, perpendicular normal force. With uneven load distribution, notch effects or angled forces, the actual local contact pressure deviates from this average and requires a more detailed stress analysis.
Common mistake: Do not equate force and pressure: the same force can create very different pressures depending on area. For fluid pressures, do not confuse gauge and absolute pressure — most technical gauges display gauge pressure relative to the atmosphere, not absolute pressure.
Because the force (body weight) is the same in both cases but spreads over a much smaller heel area. Following p = F/A, pressure rises as area falls.
Nearly: 1 bar = 100,000 Pa, 1 atm = 101,325 Pa. For most engineering estimates the difference is negligible.
1 MPa equals 1,000,000 Pa and is also equal to 1 N/mm², which is convenient for component calculations using millimetre dimensions.
No, typical tyre gauges show gauge pressure relative to the atmosphere; the actual absolute pressure inside the tyre is higher by the atmospheric pressure.