Euler-Hyperbel · σkrit = π²·E/λ²

Euler Buckling Stress Calculator

Calculate the buckling stress σkrit = π²E/λ², i.e. the compressive stress present in the member when it reaches the Euler buckling load. It is the fastest validity test of Euler theory: if σkrit exceeds the material's proportional limit, the member no longer buckles elastically and the Euler formula overestimates the capacity.

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Inputs

The compressive stress in the member when the buckling load is reached, i.e. σkrit = Fkrit/A. It is a computed comparison value, not a material strength: a member whose σkrit lies above the proportional limit never reaches that value because the material yields first.

Elastic modulus of the member material from a material table: structural steel ≈ 210 GPa, aluminium alloys ≈ 70 GPa, grey cast iron ≈ 100 GPa. Buckling stress depends only on E and slenderness – not on yield strength.

The dimensionless slenderness ratio λ = lk/i with buckling length lk = β·l and radius of gyration i = √(I/A). Source: the slenderness-ratio calculator, or a profile table together with the end conditions. Because λ appears squared in the denominator, doubling slenderness leaves a quarter of the buckling stress.

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Result

Select a target and calculate.

Calculation

σkrit = π² · E / λ²

Calculate the buckling stress σkrit = π²E/λ², i.e. the compressive stress present in the member when it reaches the Euler buckling load. It is the fastest validity test of Euler theory: if σkrit exceeds the material's proportional limit, the member no longer buckles elastically and the Euler formula overestimates the capacity.

Understand the inputs
  • Buckling stress σkrit — The compressive stress in the member when the buckling load is reached, i.e. σkrit = Fkrit/A. It is a computed comparison value, not a material strength: a member whose σkrit lies above the proportional limit never reaches that value because the material yields first.
  • Elastic modulus E — Elastic modulus of the member material from a material table: structural steel ≈ 210 GPa, aluminium alloys ≈ 70 GPa, grey cast iron ≈ 100 GPa. Buckling stress depends only on E and slenderness – not on yield strength.
  • Slenderness ratio λ — The dimensionless slenderness ratio λ = lk/i with buckling length lk = β·l and radius of gyration i = √(I/A). Source: the slenderness-ratio calculator, or a profile table together with the end conditions. Because λ appears squared in the denominator, doubling slenderness leaves a quarter of the buckling stress.
Example

A steel member with E = 210 GPa and λ = 89.44 has σkrit = π²·210,000 N/mm²/89.44² ≈ 259 N/mm². As a check: the same member with A = 20 cm² and Fkrit = 518 kN gives Fkrit/A = 518,154 N/2,000 mm² = 259 N/mm² – identical. Since the proportional limit of S235 is about 190 N/mm², σkrit here exceeds it: the member is too stocky for the Euler formula.

Assumptions and limits

Linear-elastic homogeneous material and an ideal straight member under centric load with constant cross-section. The result is usable only while σkrit stays below the material's compressive proportional limit |σP|, i.e. for λ > λ₀ = π√(E/|σP|); below that the Euler formula is inadmissible and gives unsafely high values. Initial curvature, load eccentricity, residual stresses, inelastic buckling, torsional buckling, local plate buckling of thin-walled profiles and the safety factors required by codes are excluded.

Technical article

Understand Euler buckling stress of a compression member

The buckling stress σkrit is the compressive stress present in a member exactly when it reaches the Euler buckling load. It replaces the buckling-load calculation with a stress that can be compared directly against material data – answering in one step whether Euler theory applies to the member at all.

What does this quantity describe?

Dividing the Euler buckling load Fkrit = π²EI/lk² by the cross-sectional area A and replacing I/A with the squared radius of gyration i² gives σkrit = π²E/λ² with the slenderness ratio λ = lk/i. The geometry is thus fully contained in one dimensionless number, leaving only the elastic modulus. Plotted against λ, σkrit is the Euler hyperbola: the right-hand, elastic branch of every buckling curve.

Like tyre pressure: the force alone says little; only pressure – force per area – can be compared against a rated limit. σkrit turns the buckling load into exactly such a comparable quantity that can be placed next to the material's yield or proportional limit.

Formula and variables

σkrit = π² · E / λ²

  • Buckling stress: σkrit = π²·E/λ²
  • Derivation: σkrit = Fkrit/A = π²EI/(lk²A) = π²E/λ²
  • Slenderness ratio: λ = lk/i with i = √(I/A)
  • Validity limit: σkrit ≤ |σP| or λ ≥ λ₀ = π·√(E/|σP|)
Symbol / inputMeaning
Buckling stress σkritThe compressive stress in the member when the buckling load is reached, i.e. σkrit = Fkrit/A. It is a computed comparison value, not a material strength: a member whose σkrit lies above the proportional limit never reaches that value because the material yields first.
Elastic modulus EElastic modulus of the member material from a material table: structural steel ≈ 210 GPa, aluminium alloys ≈ 70 GPa, grey cast iron ≈ 100 GPa. Buckling stress depends only on E and slenderness – not on yield strength.
Slenderness ratio λThe dimensionless slenderness ratio λ = lk/i with buckling length lk = β·l and radius of gyration i = √(I/A). Source: the slenderness-ratio calculator, or a profile table together with the end conditions. Because λ appears squared in the denominator, doubling slenderness leaves a quarter of the buckling stress.

Choose the inputs correctly

E is the material's elastic modulus from a material table (structural steel ≈ 210 GPa, aluminium ≈ 70 GPa). λ is the slenderness ratio λ = lk/i, computed from the reduced buckling length lk = β·l and the radius of gyration i = √(I/A). Both values must belong to the same member, i.e. the same end conditions and the same cross-section.

How to use the calculator

First determine λ from buckling length and section values, then compute σkrit with the elastic modulus. Then the decisive check: compare σkrit with the material's compressive proportional limit |σP|. If σkrit lies below it, the Euler calculation is admissible and you divide it by the required safety factor against buckling. If it lies above, the result is unusable – the member is too stocky and must be verified by an inelastic method or the governing code procedure.

Worked example

A steel member with E = 210 GPa and λ = 89.44 gives σkrit = π²·210,000 N/mm²/89.44² = 259.1 N/mm². Cross-check via the buckling load: the same member (I = 100 cm⁴, A = 20 cm², lk = 2,000 mm) has Fkrit = 518,154 N, and 518,154 N/2,000 mm² = 259.1 N/mm² – both routes give exactly the same value. For S235 with |σP| ≈ 190 N/mm², σkrit exceeds the proportional limit, so the Euler formula is inadmissible. Extending the same member to λ = 130 lowers σkrit to 122.6 N/mm², safely inside the elastic range.

Understand the result and units

σkrit falls quadratically with slenderness: double the slenderness leaves a quarter of the stress. Plotted against λ it forms a hyperbola that runs to infinity for small λ – and that is exactly where it is physically wrong, since no material sustains arbitrarily high stress. Every buckling curve therefore cuts the Euler hyperbola off at the limit slenderness λ₀ and replaces it in the stocky range with a line or curve derived from tests.

The calculation runs in pascal internally. E may be entered in GPa or MPa, σkrit in MPa (= N/mm²), kPa, GPa or psi. λ is dimensionless and entered as a decimal, not a percentage. In hand calculations with E in N/mm², σkrit comes out directly in N/mm².

Useful next calculation

The slenderness ratio comes from the slenderness ratio of a compression member, the corresponding force from the Euler buckling load and the validity boundary from the limit slenderness. For comparison against the material limit, see the static yield safety factor.

Typical applications

A fast validity test of Euler theory before any buckling check; comparing materials and profiles on a common stress basis; placing a member in the elastic or inelastic range of a buckling curve; plausibility-checking a buckling-load calculation via σkrit = Fkrit/A.

Assumptions, limits and common mistakes

Valid only in the linear-elastic range, i.e. for λ > λ₀ = π√(E/|σP|). Below the limit slenderness the formula returns stresses the material never reaches, and therefore unsafe results. It further assumes an ideal straight member under centric load with constant cross-section and homogeneous material. Initial curvature and load eccentricity, residual stresses from rolling or welding, inelastic buckling, torsional buckling, local plate buckling of thin-walled profiles and code-required safety factors are not covered.

Common mistake: The most serious error is using σkrit without comparing it to the proportional limit – for stocky members the result is then dangerously high. σkrit must also not be read as a material strength or a permissible stress; it is a stability limit of the ideal member and still has to be divided by the required safety factor. And as with the buckling load: a higher yield strength does not shift σkrit, because only E enters.

Frequently asked questions

What is “Euler buckling stress of a compression member” used for?

A fast validity test of Euler theory before any buckling check; comparing materials and profiles on a common stress basis; placing a member in the elastic or inelastic range of a buckling curve; plausibility-checking a buckling-load calculation via σkrit = Fkrit/A.

Where do the input values come from?

E is the material's elastic modulus from a material table (structural steel ≈ 210 GPa, aluminium ≈ 70 GPa). λ is the slenderness ratio λ = lk/i, computed from the reduced buckling length lk = β·l and the radius of gyration i = √(I/A). Both values must belong to the same member, i.e. the same end conditions and the same cross-section.

What does the result not cover?

Valid only in the linear-elastic range, i.e. for λ > λ₀ = π√(E/|σP|). Below the limit slenderness the formula returns stresses the material never reaches, and therefore unsafe results. It further assumes an ideal straight member under centric load with constant cross-section and homogeneous material. Initial curvature and load eccentricity, residual stresses from rolling or welding, inelastic buckling, torsional buckling, local plate buckling of thin-walled profiles and code-required safety factors are not covered.

Sources, method and review

  • Dankert/Dankert, Technische Mechanik, 7. Auflage 2013, Kapitel „Knickung“, Abschnitt „Stab-Knickung“: σkr = Fkr/A = π²E/λ²
  • Gross/Hauger/Schröder/Wall, Technische Mechanik 2 – Elastostatik, 15. Auflage 2024, Kapitel „Knickung“ (Grenze der elastischen Knicktheorie an der Elastizitätsgrenze)

Our method, source hierarchy and automated checks are documented on the methodology page. Read the methodology

Responsible
NormCalc-Redaktion
Last updated
2026-09-24