Springs · tensile loading

Extension spring calculator to EN 13906-2

Calculate rate, forces, spring work, and body shear stresses for a cold-formed cylindrical extension spring including initial tension.

EN13906-2
01

Spring data

EN 13906-2:2013 · cold-formed round wire, hook verification excluded

02

Results

ƒ(x)

Set the inputs and run the calculation.

Inputs and method

Extension spring to EN 13906-2

Calculate force-deflection behavior and body stress of a cylindrical extension spring.

Inputs

Wire d, mean diameter D, active coils, initial tension and working deflections describe the body; hook geometry is separate.

Initial tension must be overcome before the spring carries external load. It is strongly affected by hooks and manufacturing; a correct body calculation does not verify the hook.

Calculation

Extension force equals initial tension plus body spring force from deflection. Index and shear stress are evaluated as for a compression spring.

Example

Higher initial tension shifts the force curve upward without changing body rate.

Sources and limits: EN 13906-2; verify hooks, fatigue and manufacturing tolerances separately.

Technical article

Extension spring to EN 13906-2 in detail

Calculate force-deflection behavior and body stress of a cylindrical extension spring.

Which quantities describe the extension-spring body?

Wire diameter d, mean coil diameter D and active coil count n determine the rate of the close-wound spring body. Initial tension F0 is the force required to open the touching coils. Only above F0 does the idealized characteristic follow F = F0 + R·s. Loops, hooks and other attachments are outside the body model and require separate assessment.

Formula and variables

Extension force equals initial tension plus body spring force from deflection. Index and shear stress are evaluated as for a compression spring.

Symbol / inputMeaning
d, DWire diameter and mean coil diameter of the spring body; D is measured from wire centre to wire centre.
nNumber of active body coils; attachment coils and loops must be distinguished from it.
F0Initial tension that must be overcome before the touching coils open.
s1, s2Working deflections of the opened body, paired with total forces F1 and F2.
RSpring rate in N/mm: force increase per millimetre after F0 has been overcome.

Choose the inputs correctly

Wire d, mean diameter D, active coils, initial tension and working deflections describe the body; hook geometry is separate. Initial tension must be overcome before the spring carries external load. It is strongly affected by hooks and manufacturing; a correct body calculation does not verify the hook.

How to use the calculator

Enter wire diameter, mean coil diameter, active coils and the extension spring's initial tension. Also provide two working deflections to find the resulting tensile force within the used range.

Worked example

Higher initial tension shifts the force curve upward without changing body rate.

How to read initial tension, working force and stress

F1 and F2 are total spring forces at deflections s1 and s2 — F0 is already included and must not be added again. Rate R describes only the slope after the coils open. Corrected body stress assesses the coiled wire; it says nothing about local bending and torsional stresses in the hook. EN 13906-2 also notes that initial tension can decrease over time through relaxation.

Diameter in millimetres, force in N, deflection in millimetres, stress in MPa.

Typical applications

Designing an extension spring for a known force-deflection range, for example in return springs, tensioning mechanisms or door closers.

Assumptions, limits and common mistakes

EN 13906-2; verify hooks, fatigue and manufacturing tolerances separately.

Common mistake: Don't forget initial tension – unlike a compression spring, an extension spring only starts to stretch once this preload is exceeded; a pure rate calculation without initial tension underestimates the force needed early in the travel. Hook or loop geometry is not covered by this body calculation and is often the actual failure-critical location.

Frequently asked questions

What is initial tension?

It arises during coiling of the extension spring because the coils already touch in the unloaded state; only an external force above this tension opens the coils and produces deflection.

Why do extension springs often fail at the hook rather than the body?

Hook or loop geometry creates local stress concentrations not captured by the pure EN 13906-2 body-stress calculation, and these often govern actual fatigue life.

Can initial tension be changed after manufacturing?

Barely, without remaking the spring – it is set during the coiling process and cannot be practically adjusted on the finished part.

Is F0 already included in the reported forces?

Yes. For working deflection s the model uses F = F0 + R·s, so F0 must not be added a second time to result F1 or F2.

Does initial tension remain constant over time?

Not necessarily. EN 13906-2 notes that spring forces can decrease when initial tension relaxes over time; temperature and material condition matter.

Sources, method and review

  • EN 13906-2; verify hooks, fatigue and manufacturing tolerances separately.

Our method, source hierarchy and automated checks are documented on the methodology page. Read the methodology

Responsible
NormCalc-Redaktion
Last updated
2026-09-09
Purpose

What this calculator does

Wire diameter, mean coil diameter, active coils, initial tension, and two working deflections define the linear body characteristic. Typical uses include return springs for flaps or actuation mechanisms.

Boundary

What still needs checking

Spring hooks are often more critical than the spring body and are not verified here. Dynamic loading also requires hook transitions, stress range, material diagrams, and manufacturing effects to be assessed.