i = z₂ / z₁
More teeth on the driven gear reduce speed and ideally increase torque.
More teeth on the driven gear reduce speed and ideally increase torque.
Select a target and calculate.
More teeth on the driven gear reduce speed and ideally increase torque.
20/50 teeth give i = 2.5.
Ideal external gearing without slip or losses.
This calculator finds the missing quantity among gear ratio i and the tooth counts z₁ (pinion) and z₂ (gear) from the other two. It explains how tooth count determines the speed and torque of a gear pair — the same principle behind a bicycle's gears.
The ratio of a simple spur gear pair is the ratio of the driven gear's tooth count z₂ to the driving pinion's tooth count z₁: i = z₂/z₁. At i > 1 (a reduction), output speed falls relative to input speed, and torque rises by the same ratio if losses are neglected.
On a bicycle, a small front chainring paired with a large rear sprocket gives a large ratio: the pedals turn several times for each slower turn of the rear wheel, but with noticeably more force — ideal for climbing. A large chainring with a small sprocket reverses this, trading torque for higher speed.
i = z₂ / z₁
i = z₂ / z₁z₂ = i · z₁z₁ = z₂ / i| Symbol / input | Meaning |
|---|---|
| Gear ratio i | The gear ratio – the relationship between input and output speed (equivalently, driven to driving tooth count). i > 1 means a reduction (output turns slower, torque ideally rises); i < 1 means a speed-up. |
| Pinion teeth z₁ | The tooth count of the driving gear (pinion). Source: count them on the gear, or take it from a drawing/parts list. |
| Gear teeth z₂ | The tooth count of the driven gear (wheel). Source: count them on the gear, or take it from a drawing. |
Enter two of the three quantities. Gear ratio requires both tooth counts, z₂ requires ratio and z₁, z₁ requires ratio and z₂. Tooth counts are always positive integers; the calculator accepts intermediate values for computation, but only integer tooth counts are physically meaningful.
Select the target quantity and enter the two known values. For multi-stage gearboxes, make sure you use the tooth counts of the specific gear pair considered, not the whole gearbox — overall ratio is the product of the individual stage ratios.
Given z₁ = 20 and z₂ = 50, substitution gives i = 50/20 = 2.5. Output speed therefore falls to 1/2.5 of input speed, while ideal output torque rises to 2.5 times input torque.
A ratio of i = 2.5 means the pinion turns 2.5 times for every single turn of the larger gear. For sizing, this means: at constant input power, the output delivers more torque but at a lower speed.
Gear ratio i is a dimensionless ratio. Tooth counts z₁ and z₂ are also dimensionless and given as whole numbers.
Gear ratios are used to design gearboxes, machine tool drives, vehicle transmissions, and conveying or lifting equipment, matching a drive's speed and torque to the application.
The formula describes the ideal, loss-free ratio of a single external gear pair. Real gearboxes additionally have meshing efficiency (typically 96-99% per stage), backlash and bearing friction, so actual delivered torque falls slightly below the ideal value.
Common mistake: Do not confuse gear ratio with the ratio of shaft diameters or module — only the tooth-count ratio matters. Also, for multi-stage gearboxes, do not combine the first and last gear's tooth counts directly without correctly multiplying through the intermediate stages.
A speed reduction: output speed is lower than input speed, and ideal torque is correspondingly higher.
As the product of each individual gear stage's ratio, not their sum.
Because mechanical power P = M·ω is conserved in an ideally loss-free transmission: if angular velocity ω falls, torque M must rise by the same ratio.