T = τzul · π · d² · b / 2
As with the flat lap joint, this is a nominal shear stress evenly spread over the bond circumference; real loading concentrates at the ends of the bond line.
As with the flat lap joint, this is a nominal shear stress evenly spread over the bond circumference; real loading concentrates at the ends of the bond line.
Select a target and calculate.
As with the flat lap joint, this is a nominal shear stress evenly spread over the bond circumference; real loading concentrates at the ends of the bond line.
A 20 mm bond diameter, 30 mm engagement length and an 8 MPa allowable shear stress give T = 8 MPa · π · (20 mm)² · 30 mm / 2 ≈ 150.8 N·m.
Nominal shear stress evenly distributed over circumference and engagement length; real bonded joints under torsion show an uneven stress distribution, additionally influenced by joint clearance, bond-line thickness and surface preparation.
This calculator finds the approximately transmissible torque capacity of a cylindrical bonded shaft-hub joint from bond diameter, engagement length and allowable shear stress.
In a cylindrical bonded joint under torsion, shear stress acts tangentially over the entire circumference of the bonded surface. Rearranging the nominal, evenly distributed shear stress τ = 2T/(π·d²·b) gives the approximately transmissible torque capacity T = τallow·π·d²·b/2.
Picture the cylindrical bond line as many small lever arms acting in parallel, all at distance d/2 from the rotation axis: each area element contributes its share to the total moment, and summing over the full circumference and engagement length gives the transmissible torque.
T = τzul · π · d² · b / 2
T = τallow·π·d²·b/2τallow = 2T/(π·d²·b)d = √(2T/(τallow·π·b))| Symbol / input | Meaning |
|---|---|
| Transmissible torque T | Approximate transmissible torque of the cylindrical bond line. |
| Bond diameter d | Diameter of the cylindrical bonded surface between shaft and hub. |
| Bond width (engagement length) b | Axial length of the cylindrical bond line. |
| Allowable shear stress τzul | Bond strength divided by safety factor; typical adhesive shear strengths are roughly 5 to 20 MPa. |
Bond diameter d, axial engagement length b and allowable shear stress τallow set the transmissible torque. τallow should come from the adhesive's bond strength, typically roughly 5 to 20 MPa, divided by an appropriate safety factor.
Enter bond diameter, engagement length and allowable shear stress to compute transmissible torque. For a sizing question — what diameter or engagement length a target torque needs — choose d or b as the target.
A 20 mm bond diameter, 30 mm engagement length and 8 MPa allowable shear stress give T = 8 MPa · π · (20 mm)² · 30 mm / 2 ≈ 150.8 N·m.
A transmissible torque of 150.8 N·m at just 20 mm diameter shows the basic suitability of cylindrical bonded joints for compact shaft-hub connections — diameter enters capacity with the square, while engagement length enters only linearly.
Diameter and engagement length are given in mm, stress in MPa, and the resulting torque in N·m.
In the formula T = τallow·π·d²·b/2, diameter appears twice: once through the lever arm d/2 that converts a circumferential force into a moment, and once through the circumference π·d that helps set the available bonded area. Both effects multiply, so doubling diameter at the same engagement length quadruples transmissible torque. Engagement length b, by contrast, enters only once through bonded area and therefore acts only linearly on torque — for the same added space, a larger diameter is usually more effective than a correspondingly longer engagement.
The calculation is used for pre-sizing bonded shaft-hub joints, for example sensor or coupling attachments where a positive-fit or friction-fit connection would be unfavorable for space or weight reasons; the same nominal stress model applies analogously to cylindrical brazed joints with a correspondingly higher allowable stress.
The model assumes shear stress evenly distributed over circumference and engagement length. Volkersen-type analyses show that actual stress distribution in cylindrical bonded joints under torsion is strongly uneven and concentrates at the axial ends of the joint; joint clearance, bond-line thickness and surface preparation additionally affect real capacity substantially.
Common mistake: A common mistake is arbitrarily increasing engagement length to reach a higher torque, even though real capacity grows more slowly than the nominal formula predicts because of the uneven stress distribution. It is also easy to carry over a τallow value determined for flat lap joints unchanged to the cylindrical geometry, even though joint clearance and cure conditions can differ for a round bonded joint.
Because diameter sets both the lever arm and, via circumference, the bonded area, while engagement length enters only through area; see the section above.
Depending on the adhesive system and safety margin applied, allowable values often fall around 5 to 20 MPa; the specific adhesive's datasheet governs.
Yes, the nominal stress model is identical; brazed joints simply use a markedly higher allowable shear stress.
It shows that shear stress in a cylindrical bond line under torsion concentrates at the axial ends of the joint rather than distributing evenly, similar to the flat lap joint case.
Choose d or b as the target and enter the desired torque along with the other dimension and allowable stress, keeping in mind that diameter acts with the square.