lü = F/(b·τzul) (Vorbemessung)

Adhesive Overlap Length Calculator

This pre-sizing step sets only the nominal mean stress; beyond a certain length, additional overlap adds little real capacity because of the uneven stress distribution.

MINTSI
01

Inputs

Approximate minimum overlap length for the chosen allowable stress.

Longitudinal force in the plane of the overlapping adherends, parallel to the bond line and overlap length. It nominally loads the adhesive in shear; it is not tensile force perpendicular to the bonded surface.

Width of the bond line, transverse to the load direction.

Bond strength divided by safety factor, τzul = τKB/S; guideline values from the adhesive datasheet.

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Result

Select a target and calculate.

Load case in section
Single-lap joint with longitudinal forces parallel to the bond areaThe upper adherend extends right and the lower one left. A thin horizontal adhesive layer lies between them. Force F pulls the lower part left and the upper part right. The overlap length is l_u; width b runs perpendicular to the drawing.FFAdherend 1Adherend 2lü = overlapAdhesive layerAK = b · lü
Two overlapping flat adherends, not a butt joint. Opposing forces F act along the adherends and parallel to the bonded surface. The adhesive lies between the overlapped faces; its area Aₖ is the shown overlap length times width b perpendicular to the section. The offset load paths can also cause bending and peel stress; this calculator includes only mean shear stress τ = F/Aₖ.
Calculation

lü = F / (b · τzul)

This pre-sizing step sets only the nominal mean stress; beyond a certain length, additional overlap adds little real capacity because of the uneven stress distribution.

Understand the inputs
  • Required overlap length lü — Approximate minimum overlap length for the chosen allowable stress.
  • Transmitted force F — Longitudinal force in the plane of the overlapping adherends, parallel to the bond line and overlap length. It nominally loads the adhesive in shear; it is not tensile force perpendicular to the bonded surface.
  • Bond width b — Width of the bond line, transverse to the load direction.
  • Allowable nominal shear stress τzul — Bond strength divided by safety factor, τzul = τKB/S; guideline values from the adhesive datasheet.
Example

5,000 N at a 25 mm bond width and an allowable stress of 10 MPa give a required overlap length of lü = 5,000 N / (25 mm · 10 MPa) = 20 mm.

Assumptions and limits

Pure pre-sizing based on nominal mean stress; actual edge stress concentration, peel stresses and adherend stiffness are excluded and require separate verification.

Technical article

Understand Adhesive Overlap Length Calculator

This calculator finds the approximately required overlap length of an adhesive joint from the transmitted force, bond width and an allowable nominal shear stress.

What does this quantity describe?

This calculator applies to a single-lap joint under tensile-shear loading: longitudinal force F acts parallel to the bonded surface and overlap, so the adhesive is nominally loaded in shear. It does not mean tensile force perpendicular to the bonded surface. Rearranging τ = F/(b·lu) gives lu = F/(b·τallow); τallow usually comes from bond strength divided by a safety factor.

This is like sizing a beam's cross-section for an allowable bending stress: given the load and the allowable stress, the stress formula is solved for the needed geometric quantity, rather than checking stress for a given geometry.

Formula and variables

lü = F / (b · τzul)

  • lu = F/(b·τallow)
  • F = lu·b·τallow
  • τallow = F/(lu·b)
Symbol / inputMeaning
Required overlap length lüApproximate minimum overlap length for the chosen allowable stress.
Transmitted force FLongitudinal force in the plane of the overlapping adherends, parallel to the bond line and overlap length. It nominally loads the adhesive in shear; it is not tensile force perpendicular to the bonded surface.
Bond width bWidth of the bond line, transverse to the load direction.
Allowable nominal shear stress τzulBond strength divided by safety factor, τzul = τKB/S; guideline values from the adhesive datasheet.

Choose the inputs correctly

F is the longitudinal force parallel to the bond line. Bond width b is transverse to F; the required overlap length lu is measured in the force direction. τallow is the allowable nominal shear stress and should come from the specific adhesive's bond strength divided by an appropriate safety factor.

How to use the calculator

Enter the force to be transmitted, the available or desired bond width, and the allowable stress to get the required overlap length. Then check the result against the literature rule of thumb lu ≈ (10-20)·t (t = smallest component thickness) as a plausibility check.

Worked example

5,000 N at a 25 mm bond width and an allowable stress of 10 MPa give a required overlap length of lu = 5,000 N / (25 mm · 10 MPa) = 20 mm.

Understand the result and units

A required length of 20 mm at 25 mm width gives a length-to-width ratio of 0.8 — a plausible value for a compact, well-utilized lap joint. Overlaps markedly longer than the lu ≈ (10-20)·t rule of thumb suggests add little further capacity because of the uneven stress distribution.

Force is given in N, width and overlap length in mm, and allowable stress in MPa (N/mm²).

Cross-checking with the thickness rule of thumb

Besides the force-based calculation, the literature cites an independent rule of thumb for good utilization of bond strength in light metals: lu ≈ (10 to 20)·t, where t is the smallest thickness of the overlapped parts. If the force-based length deviates strongly from this range — for example because allowable stress is set very low or force very high — a second look is worthwhile: the chosen geometry may be unfavorable for a plain lap joint, and a different joint type or additional design measures may be preferable.

Typical applications

The calculation is used in pre-design to set an initial overlap length for a known load and available adhesive system, before the final joint is checked in detail.

Assumptions, limits and common mistakes

This is a pure pre-sizing step based on nominal mean stress. It captures neither the real stress concentration at overlap ends nor peel stresses, adherend stiffness, temperature or aging effects. For very large computed overlap lengths, check whether a stiffer joint type or multiple bond points would be more sensible, since real capacity does not grow proportionally with length.

Common mistake: A common mistake is using τallow as the manufacturer's bare bond strength τKB without a safety margin — safety factors of 1.5 to 2.5 against τKB are typical. It is also easy to adopt the computed length uncritically, even though beyond a certain length additional area barely contributes to capacity.

Frequently asked questions

What load direction is assumed for F?

F runs parallel to the bonded surface and the required overlap length. The calculator therefore sizes for nominal shear stress, not direct tensile stress perpendicular to the bonded surface.

Where do I get the allowable stress τallow?

From the adhesive's bond strength in its datasheet, divided by a safety factor appropriate to the application, typically around 1.5 to 2.5.

What if the computed length becomes very long?

Check whether a wider bond, a stronger adhesive, a stiffer joint type or multiple bond points would be more economical, since a very long overlap does not fully use its area because of the uneven stress distribution.

How does the result compare with the lu ≈ (10-20)·t rule of thumb?

Both approaches should land in the same order of magnitude; a large mismatch signals an unfavorable combination of load, area and part thickness for the chosen joint type.

Can I vary width instead of length?

Yes, since AK = b·lu is symmetric in b and lu, the other dimension can be enlarged to reach the same area when space is limited in one direction.

Is a longer overlap always safer?

Not proportionally: beyond a certain length, additional area in the middle barely contributes to load transfer, so real safety grows more slowly than the nominal calculation suggests.