Tmotor = F·d/(2·η)
At the ideal pinion, Tp = F·r; meshing, bearing and gearbox losses raise the torque actually required at the drive.
At the ideal pinion, Tp = F·r; meshing, bearing and gearbox losses raise the torque actually required at the drive.
Select a target and calculate.
At the ideal pinion, Tp = F·r; meshing, bearing and gearbox losses raise the torque actually required at the drive.
F=5,000 N, d=50 mm and η=0.9 give an ideal pinion torque Tp=F·d/2=125 N·m and required drive torque Tmotor=125/0.9≈138.9 N·m.
Steady, quasi-static view with constant η; acceleration torque from moving masses, backlash, preload and dynamic load peaks are excluded and must be added separately.
This calculator determines the torque a drive must actually supply at the pinion shaft of a rack-and-pinion drive to generate a required feed force. It extends the plain lever-arm relation Tp=F·r with the drive efficiency that many simple rules of thumb omit.
At the ideal, lossless pinion, Tp=F·r=F·d/2 with pitch radius r=d/2. Meshing friction, bearing friction and any upstream gearbox consume additional power, so the drive itself must supply a torque increased by efficiency η: Tmotor=Tp/η=F·d/(2η).
Tmotor = F·d/(2·η)
| Symbol / input | Meaning |
|---|---|
| Required drive torque Tmotor | Torque to be supplied at the drive (motor or gearbox output shaft), including losses. |
| Required feed force F | Tangential force at the rack needed for feed, acceleration and any process load. |
| Pinion pitch diameter d | Pitch diameter of the meshing pinion; halved it gives the effective lever arm. |
| Drive efficiency η | Overall efficiency of meshing, bearings and any upstream gearbox between motor and pinion. |
F is the force actually needed at the rack for feed, acceleration and process loads. d is the pitch diameter of the meshing pinion. η is the overall efficiency between motor shaft and pinion, typically 0.85 to 0.95 for a single-stage, ball-bearing-supported mesh.
Take F from the application's load analysis, including friction, acceleration and any process forces. Take d from the chosen pinion datasheet. Assume η conservatively, or take it from manufacturer data if an upstream gearbox is present.
F=5,000 N, d=50 mm and η=0.9 give an ideal pinion torque Tp=F·d/2=125 N·m and an actually required drive torque Tmotor=125/0.9≈138.9 N·m.
The smaller η, the larger the margin above the ideal pinion torque; at η=0.7 it is already about 43% more than at η=0.9. Assuming too high an η undersizes the drive.
F is a force, d a length and η dimensionless. Tmotor is output as a torque.
The base relation Tp=F·r is widely accepted drive-engineering knowledge, see e.g. linearmotiontips.com; that sizing guide explicitly flags efficiency as an open point of simplified rules of thumb. This calculator fills exactly that gap without inventing manufacturer-specific mesh or gearbox data.
Preliminary sizing of servo drives for rack-and-pinion axes in machine tools, gantry systems and handling axes, before adding acceleration torque and peak loads from moving inertia.
Steady, quasi-static view with constant efficiency. Acceleration torque from moving masses, backlash and mesh preload, dynamic load peaks, and a separate reduction step for an upstream gearbox are excluded and must be added separately.
Common mistake: Do not confuse pinion radius with pitch diameter; d is the full diameter, and d/2 appears in the numerator. Do not assume η=1 when a gearbox or lubricated mesh with noticeable losses is actually present.
No. F must already include all static and dynamic force components at the rack; an additional acceleration torque from rotating drive-part inertia must be added separately.
For a single-stage, ball-bearing-supported mesh, 0.85 to 0.95 is typical; with an additional upstream gearbox, overall efficiency drops by that gearbox's own efficiency.
Many simple calculators only give the ideal pinion torque Tp=F·r without efficiency; this calculator additionally gives the torque actually required at the drive, increased by η.