P = (F₁ − F₂) · v
Only the difference between tight- and slack-side tension does work; it is multiplied by belt speed.
Only the difference between tight- and slack-side tension does work; it is multiplied by belt speed.
Select a target and calculate.
Only the difference between tight- and slack-side tension does work; it is multiplied by belt speed.
F₁ = 256.6 N, F₂ = 100 N and v = 25 m/s give P ≈ 3.92 kW.
Steady-state operation; belt mass, centrifugal effects and efficiency losses are excluded.
This calculator finds the missing quantity among transmitted power P, tight-side tension F₁, slack-side tension F₂ and belt speed v from the other two. It shows why only the difference between the two belt-strand tensions actually does work — not the full tight-side tension.
The mechanical power transmitted by a belt drive is the product of the tension difference between the tight and slack strands and belt speed: P = (F₁ − F₂)·v. Slack-side tension F₂ merely provides preload and does not itself contribute to useful power.
When starting up a belt-driven conveyor or compressor, tight-side tension F₁ rises well above slack-side tension F₂ while the belt already runs at nearly constant speed. Manufacturer guidance typically has V-belts running at about 20 to 25 m/s, rarely above 30 m/s — at higher speeds, centrifugal effects and belt wear increase disproportionately.
P = (F₁ − F₂) · v
P = (F₁ − F₂) · vF₁ = P/v + F₂F₂ = F₁ − P/vv = P / (F₁ − F₂)| Symbol / input | Meaning |
|---|---|
| Transmitted power P | Mechanical power delivered by the belt drive. |
| Tight-side tension F₁ | Force in the tight (driving) belt strand. |
| Slack-side tension F₂ | Force in the slack belt strand. |
| Belt speed v | Belt's linear travel speed. |
Enter two of the four quantities. F₁ and F₂ must belong to the same operating point; v is the belt's actual travel speed, not a pulley's rotational speed.
Select the target quantity and enter the other known values with units. If needed, first find belt speed using the existing tangential-speed calculator from pulley diameter and rotational speed.
Given F₁ = 256.6 N, F₂ = 100 N and v = 25 m/s, substitution gives P = (256.6 − 100) · 25 ≈ 3,916 W ≈ 3.92 kW.
Transmitted power of 3.92 kW shows the mechanical power actually usable at the output for this tension difference and belt speed. Required motor power additionally needs the belt drive's efficiency factored in.
Forces in newtons (N), speed in m/s, power in watts (W) or kilowatts (kW).
The formula is used to size belt drives for compressors, fans, pumps and conveyors, and to back-calculate transmittable power for existing drives.
The formula assumes steady-state operation at constant belt speed. At high speeds, centrifugal force reduces the belt's contact pressure on the pulley and therefore the actually transmittable tension difference; belt mass and efficiency losses are not included here.
Common mistake: Do not substitute the full tight-side tension F₁ for the tension difference (F₁ − F₂) in the power formula — only the difference between the two strand tensions does work. Also, don't confuse belt speed with a pulley's rotational speed; the two are linked through pulley diameter but are different quantities.
Because slack-side tension F₂ is already present as preload and performs no additional work. Only the portion beyond preload (F₁ − F₂) actually transmits power.
Usually around 20 to 25 m/s, rarely exceeding 30 m/s in practice, since centrifugal effects and wear increase markedly at higher speeds.
The maximum tension difference (F₁ − F₂) a belt can transmit without slipping is bounded by the capstan equation; the power calculated here must not exceed that limit.