P = kAΔT/L

Heat conduction through a plane wall

Good insulation has low conductivity; area and temperature difference increase loss.

MINTSI
01

Inputs

Steady heat flow without surface resistances.

Material property; mineral wool about 0.035–0.045 W/(m·K).

Wall area normal to heat flow.

Inside minus outside temperature magnitude.

Thickness in heat-flow direction.

02

Result

Select a target and calculate.

Calculation

P = k · A · ΔT / L

Good insulation has low conductivity; area and temperature difference increase loss.

Understand the inputs
  • Heat flow PSteady heat flow without surface resistances.
  • Thermal conductivity kMaterial property; mineral wool about 0.035–0.045 W/(m·K).
  • Area AWall area normal to heat flow.
  • Temperature difference ΔTInside minus outside temperature magnitude.
  • Wall thickness LThickness in heat-flow direction.
Example

0.04 W/(m·K) · 10 m² · 20 K / 0.8 m = 10 W.

Assumptions and limits

Plane homogeneous wall and steady one-dimensional heat flow.

Sources