Busch 2006, Abschnitt 2.7.1, Gl. (2.64) Energieinhalt des Magnetfeldes

Energy stored in an inductor's magnetic field

Stored energy grows with the square of current, similar to a capacitor's stored energy growing with the square of voltage.

MINTSI
01

Inputs

Energy stored in the magnetic field at steady current I.

Coil inductance with no saturation over the considered current range.

Steady current through the coil at which energy is evaluated.

02

Result

Select a target and calculate.

Calculation

W = ½·L·I²

Stored energy grows with the square of current, similar to a capacitor's stored energy growing with the square of voltage.

Understand the inputs
  • Magnetic energy WEnergy stored in the magnetic field at steady current I.
  • Inductance LCoil inductance with no saturation over the considered current range.
  • Coil current ISteady current through the coil at which energy is evaluated.
Example

L=100 mH and I=1 A give W=½·0.1·1²=0.05 J.

Assumptions and limits

Constant, saturation-free inductance; winding resistance and its resistive losses are not included.

Technical article

Understand Energy stored in an inductor's magnetic field

This calculator determines the energy stored in a current-carrying inductor's magnetic field, the magnetic counterpart to the existing electrical energy of a charged capacitor.

What does this quantity describe?

Building up current in a coil stores energy in its magnetic field: W=½·L·I². This energy is released again at switch-off, e.g. as an induced voltage spike.

Formula and variables

W = ½·L·I²

  • W = ½·L·I²
Symbol / inputMeaning
Magnetic energy WEnergy stored in the magnetic field at steady current I.
Inductance LCoil inductance with no saturation over the considered current range.
Coil current ISteady current through the coil at which energy is evaluated.

Choose the inputs correctly

L is the coil's inductance, I the steady current at which energy is evaluated.

How to use the calculator

Take L from a datasheet or measurement and use the actual operating current I.

Worked example

L=100 mH and I=1 A give W=½·0.1·1²=0.05 J.

Understand the result and units

Energy grows with the square of current; doubling current quadruples stored energy.

L is an inductance, I a current. W is output as an energy.

Useful next calculation

Current decay after switch-off follows from RL coil current decay; the electrical counterpart is parallel-plate capacitor capacitance.

Typical applications

Estimating energy released at switch-off in relay, contactor and solenoid-valve coils, and a basis for sizing freewheeling paths.

Assumptions, limits and common mistakes

Constant, saturation-free inductance; winding resistance and its resistive losses are not included.

Common mistake: Do not confuse a switch-on transient peak current with the steady current at which energy is actually to be evaluated.

Frequently asked questions

What is “Energy stored in an inductor's magnetic field” used for?

Estimating energy released at switch-off in relay, contactor and solenoid-valve coils, and a basis for sizing freewheeling paths.

Where do the input values come from?

L is the coil's inductance, I the steady current at which energy is evaluated.

What does the result not cover?

Constant, saturation-free inductance; winding resistance and its resistive losses are not included.

Sources, method and review

  • Rudolf Busch, Elektrotechnik und Elektronik für Maschinenbauer und Verfahrenstechniker, 4th ed. 2006, Abschnitt 2.7.1, Gl. (2.64) Wm = L·I²/2 (local chapter PDF)

Our method, source hierarchy and automated checks are documented on the methodology page. Read the methodology

Responsible
NormCalc-Redaktion
Last updated
2026-09-16