Dubbel Festigkeitslehre C 2.4.6 Schubspannungen am geraden Träger: max τ = 1,5·FQ/A (Rechteck, parabolische Verteilung)

Maximum shear stress in a rectangular cross-section

Shear stress is distributed parabolically over a rectangular section; its maximum at the neutral axis is 1.5 times the average stress Q/A.

MINTSI
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Inputs

Peak shear stress in the cross-section, at the neutral axis.

Shear force at the considered location from the internal-force analysis.

Width of the rectangular section perpendicular to the force direction.

Height of the rectangular section in the direction of the force.

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Result

Select a target and calculate.

Calculation

τmax = 1.5·Q/(b·h)

Shear stress is distributed parabolically over a rectangular section; its maximum at the neutral axis is 1.5 times the average stress Q/A.

Understand the inputs
  • Maximum shear stress τmaxPeak shear stress in the cross-section, at the neutral axis.
  • Shear force QShear force at the considered location from the internal-force analysis.
  • Section width bWidth of the rectangular section perpendicular to the force direction.
  • Section height hHeight of the rectangular section in the direction of the force.
Example

Q=5,000 N, b=50 mm and h=100 mm give A=5,000 mm² and τmax=1.5·5,000/5,000=1.5 MPa.

Assumptions and limits

Homogeneous, linear-elastic rectangular section and pure transverse shear with no simultaneous torsion; thin-walled or composite sections follow a different distribution.

Technical article

Understand Maximum shear stress in a rectangular cross-section

This calculator determines the maximum transverse shear stress in a rectangular cross-section, complementing existing beam and bending-stress calculators that report bending stress but not transverse shear stress.

What does this quantity describe?

For a rectangular section, transverse shear stress is distributed parabolically over the height and peaks at the neutral axis: τmax=1.5·Q/A with A=b·h.

Formula and variables

τmax = 1.5·Q/(b·h)

  • τmax = 1.5·Q/(b·h)
  • τaverage = Q/(b·h)
Symbol / inputMeaning
Maximum shear stress τmaxPeak shear stress in the cross-section, at the neutral axis.
Shear force QShear force at the considered location from the internal-force analysis.
Section width bWidth of the rectangular section perpendicular to the force direction.
Section height hHeight of the rectangular section in the direction of the force.

Choose the inputs correctly

Q is the shear force at the considered location, b the section width and h the section height in the direction of the force.

How to use the calculator

Take Q from the beam's internal-force analysis, b and h from the actual rectangular cross-section.

Worked example

Q=5,000 N, b=50 mm and h=100 mm give A=5,000 mm² and τmax=1.5·5,000/5,000=1.5 MPa.

Understand the result and units

The 1.5 factor distinguishes the actual peak stress from the often first-computed average shear stress Q/A; other section shapes (I-beam, circle) use a different factor.

Q is a force, b and h are lengths. τmax is output as a stress.

Useful next calculation

For bending stress of the same section, mechanical stress is the counterpart.

Typical applications

Checking shear stress alongside bending stress for short, heavily loaded beams and brackets with rectangular sections, where shear can govern.

Assumptions, limits and common mistakes

Homogeneous, linear-elastic rectangular section and pure transverse shear with no simultaneous torsion; thin-walled, composite or non-rectangular sections follow a different distribution and shape factor.

Common mistake: Do not forget the 1.5 factor and do not equate τmax with the average shear stress Q/A.

Frequently asked questions

What is “Maximum shear stress in a rectangular cross-section” used for?

Checking shear stress alongside bending stress for short, heavily loaded beams and brackets with rectangular sections, where shear can govern.

Where do the input values come from?

Q is the shear force at the considered location, b the section width and h the section height in the direction of the force.

What does the result not cover?

Homogeneous, linear-elastic rectangular section and pure transverse shear with no simultaneous torsion; thin-walled, composite or non-rectangular sections follow a different distribution and shape factor.

Sources, method and review

  • Dubbel, Festigkeitslehre C 2.4.6 Schubspannungen am geraden Träger: τxz parabolisch, max τ = 1,5·FQ/A = 1,5·τm beim Rechteck (lokale Kapitel-PDF)

Our method, source hierarchy and automated checks are documented on the methodology page. Read the methodology

Responsible
NormCalc-Redaktion
Last updated
2026-09-16