A = Q / v
Larger area lowers velocity, noise and pressure loss.
Larger area lowers velocity, noise and pressure loss.
Select a target and calculate.
Larger area lowers velocity, noise and pressure loss.
60 l/min at 1 m/s needs 1,000 mm².
Full circular pipe; fitting losses are excluded.
This calculator finds the open pipe cross-section needed for a target flow and an allowable velocity — or solves for either of the other two quantities. It shows how a chosen velocity limit directly yields the minimum pipe cross-section for an application.
The cross-section required for a given flow at a specified allowable velocity is A = Q/v. A larger cross-section lowers velocity, and with it noise, erosion and pressure loss, at the same flow.
When sizing a cold-water line under the Uniform Plumbing Code, velocity in copper tube must not exceed about 2.4 m/s. For a given target flow, that directly yields the minimum required cross-section — choosing a smaller, cheaper pipe pushes velocity above this limit, raising the risk of noise and erosion problems.
A = Q / v
A = Q / vQ = v · Av = Q / A| Symbol / input | Meaning |
|---|---|
| Open area A | The required open pipe area to deliver the target flow at the allowable velocity. Computed as a result from Q/v; from it the needed inner diameter d = √(4A/π) can be derived. |
| Target flow Q | The required design flow of the line. Source: the system specification, a pump curve, or the sum of demand from all connected consumers. |
| Allowable velocity v | The allowable (target) flow velocity – a limit against noise, erosion and pressure loss, not a measured value. Typical values: water in pressure lines about 1–3 m/s, suction lines about 0.5–1.5 m/s. |
Enter two of the three quantities. Cross-section requires flow and allowable velocity, flow requires cross-section and velocity, velocity requires cross-section and flow. Choose v based on recognized limits for the medium and material.
Select the target quantity and enter the two known values with units. Round the calculated minimum cross-section up to the next available nominal pipe size afterward, never down.
Given Q = 60 l/min and v = 1 m/s, substitution gives A = 60 l/min / 1 m/s = 1,000 mm².
A required cross-section of 1,000 mm² corresponds, for a circular pipe, to an internal diameter of about 35.7 mm. Choosing any smaller actual cross-section pushes velocity above the assumed value at the same flow.
Cross-section in mm² or cm², flow in l/min or m³/h, velocity in m/s. Converting to a pipe diameter uses A = π·d²/4.
The calculation is used for pipe sizing in potable water and heating installations, industrial process lines, and pump and fitting connection planning, to ensure a target flow at an allowable velocity.
The formula gives the required net cross-section for uniformly distributed flow. Fittings, bends, constrictions and local flow disturbances are not included here and need a separate pressure-loss analysis.
Common mistake: Do not round the calculated minimum cross-section down when no exactly matching nominal size is available — round up to the next larger nominal size instead, since an undersized cross-section exceeds the allowable velocity. Also, don't confuse radius with diameter when converting to a pipe diameter.
For a circular cross-section, A = π·d²/4 gives an internal diameter of d = √(4·A/π) ≈ 35.7 mm.
Actual flow velocity rises above the assumed limit at the same flow, with correspondingly higher risk of noise, erosion and pressure loss.
Always round up to the next larger available nominal size, since rounding down exceeds the allowable velocity.