What is calculated?
In radial conduction, area increases with radius. The diameter ratio therefore appears logarithmically in resistance.
Equations
Rλ = ln(da/di)/(2πλL)
Q̇ = ΔT/Rλ
Calculate the radial conductive heat loss through cylindrical pipe insulation.
Enter values and run the calculation.
In radial conduction, area increases with radius. The diameter ratio therefore appears logarithmically in resistance.
Rλ = ln(da/di)/(2πλL)
Q̇ = ΔT/Rλ
Compare insulation thicknesses and estimate distribution losses.
Homogeneous-insulation conduction only; films, radiation, pipe wall, supports and moisture excluded.
The entered difference is across insulation; fluid and air temperatures require extra film resistances.
No; cylindrical geometry makes the relation logarithmic.
Dubbel, thermodynamics, heat transmission through pipes (local source, 2026-09-09).
The source supports the equation structure; this calculator does not claim a complete standards verification.