P ≈ VF·IF·D

Diode forward conduction loss

While the diode conducts, loss is forward voltage times forward current; averaged over a periodic switching cycle it additionally scales with duty cycle.

MINTSI
01

Inputs

Power loss while the diode is conducting.

Loss averaged over one switching period.

Voltage drop across the conducting diode; silicon ≈ 0.6–1.0 V, Schottky ≈ 0.2–0.4 V.

Current through the diode during conduction.

Fraction of the switching period during which the diode actually conducts; 1 means continuous conduction.

02

Result

Select a target and calculate.

Calculation

Pinst = VF · IF; Pavg = Pinst · D

While the diode conducts, loss is forward voltage times forward current; averaged over a periodic switching cycle it additionally scales with duty cycle.

Understand the inputs
  • Instantaneous loss PinstPower loss while the diode is conducting.
  • Average loss PavgLoss averaged over one switching period.
  • Forward voltage VFVoltage drop across the conducting diode; silicon ≈ 0.6–1.0 V, Schottky ≈ 0.2–0.4 V.
  • Forward current IFCurrent through the diode during conduction.
  • Duty cycle DFraction of the switching period during which the diode actually conducts; 1 means continuous conduction.
Example

VF = 0.7 V and IF = 5 A give an instantaneous loss of 3.5 W; at a 50% duty cycle the average loss is 1.75 W.

Assumptions and limits

Constant forward voltage during conduction; reverse recovery, switching and dynamic losses are excluded.

Technical article

Understand Diode forward conduction loss

This calculator finds the instantaneous and switching-period-averaged forward conduction loss of a diode from forward voltage, forward current and duty cycle, using a simplified constant-value model.

What does this quantity describe?

While a diode conducts in the forward direction, forward voltage VF drops across it as current IF flows through it; the instantaneous power dissipated as heat is Pinst = VF·IF. If the diode conducts only part of a periodic switching cycle — the duty cycle D — then, assuming constant VF and IF during conduction, the loss averaged over the period is Pavg = Pinst·D.

Picture a tap that is only open part of the time: instantaneous flow rate is constant while the tap is open, but the flow rate averaged over a longer time falls in proportion to the fraction of time the tap was actually open.

Formula and variables

Pinst = VF · IF; Pavg = Pinst · D

  • Pinst = VF · IF
  • Pavg = Pinst · D
  • D = Pavg / Pinst
Symbol / inputMeaning
Instantaneous loss PinstPower loss while the diode is conducting.
Average loss PavgLoss averaged over one switching period.
Forward voltage VFVoltage drop across the conducting diode; silicon ≈ 0.6–1.0 V, Schottky ≈ 0.2–0.4 V.
Forward current IFCurrent through the diode during conduction.
Duty cycle DFraction of the switching period during which the diode actually conducts; 1 means continuous conduction.

Choose the inputs correctly

Forward voltage VF and forward current IF set the instantaneous loss; the additional duty cycle D between 0 and 1 gives the averaged loss. VF depends on load and temperature and should be read from the forward characteristic in the datasheet at the actual operating point (IF and junction temperature) rather than assumed as a blanket constant across the whole current range.

How to use the calculator

Select the target quantity. For instantaneous loss, enter VF and IF; for average loss, additionally enter duty cycle D. To estimate the total loss of several identical, simultaneously conducting diodes, multiply Pavg by the number of diodes afterward.

Worked example

VF = 0.7 V and IF = 5 A give an instantaneous loss of Pinst = 3.5 W. If the diode conducts only 50% of a switching period — for example as a freewheeling diode in a buck converter at a 50% duty cycle — the average loss is Pavg = 3.5 W · 0.5 = 1.75 W.

Understand the result and units

An average loss of 1.75 W must be conducted away through the diode package and any heatsink to the ambient; the linked junction temperature calculator, combined with the diode's thermal resistance RthJA, can be used to estimate the resulting junction temperature.

Forward voltage is given in V, forward current in A, power loss in W, and duty cycle D dimensionless between 0 and 1 or as a percentage.

Conduction loss versus switching loss

Total diode loss in a switching application consists of conduction loss (this calculator) plus switching loss. Conduction loss occurs while the diode conducts and scales with VF·IF·D. Switching loss occurs during the transition between blocking and conducting states, especially from reverse-recovery charge, which briefly causes a reverse current during fast turn-off. At low switching frequencies, conduction losses usually dominate; at high switching frequencies in the hundreds-of-kHz-to-MHz range, switching losses can dominate instead — which is why Schottky diodes, with negligible reverse-recovery charge, are preferred there.

Typical applications

The relationship is used to estimate power loss for rectifier, freewheeling and protection diodes in power supplies and switching regulators, to pre-select diode package and heatsink, and for a rough efficiency comparison between silicon and Schottky diodes, since Schottky diodes have lower conduction losses due to their lower VF.

Assumptions, limits and common mistakes

The model captures only conduction losses under an assumed constant forward voltage and neglects the real VF(IF,Tj) characteristic, which is nonlinear with both current and temperature. Reverse-recovery loss at turn-off, dynamic switching losses at turn-on and turn-off, and reverse leakage loss are not included and must be additionally considered for fast-switching applications.

Common mistake: A common mistake is considering only conduction losses for fast-switching applications such as high-kHz switch-mode power supplies, even though switching and reverse-recovery losses can there make up a substantial, sometimes dominant, share of total losses. VF is also sometimes used as a fixed value independent of actual operating current, even though VF rises noticeably with increasing IF.

Frequently asked questions

What is forward voltage VF?

It is the voltage drop across the diode while current flows in the forward direction; it is typically 0.6–1.0 V for silicon diodes and 0.2–0.4 V for Schottky diodes.

Why does electrical power at the diode become heat?

Because the diode has a voltage drop while current flows through it during conduction; the product of voltage and current is power, which is dissipated as heat in the semiconductor die and package.

What's the difference between silicon and Schottky diodes for losses?

Schottky diodes have a lower forward voltage than silicon diodes and therefore lower conduction losses at the same current; they also have negligible reverse-recovery charge, giving them low switching losses even at high switching frequencies.

How does VF depend on forward current?

VF rises with increasing IF, initially approximately logarithmically and increasingly linearly at high currents due to the diode's ohmic bulk resistance; a single fixed VF value is therefore only accurate at one specific operating point.

How do I combine this with the junction temperature calculator?

Use the average loss Pavg computed here as the input P for the junction temperature calculator, together with ambient temperature and the diode's thermal resistance RthJA, to estimate the resulting junction temperature.