Busch 2006, Abschnitt 5.8.1 Komplexer Widerstand (Beispiel R = 10 Ω, L = 64 mH, 50 Hz → Z = 22,4 Ω)

RL series circuit impedance

With no capacitor, impedance follows from the geometric sum of resistance and inductive reactance.

MINTSI
01

Inputs

Magnitude of the complex AC impedance of the series circuit.

Resistive part, e.g. choke or motor-winding resistance.

Effective inductance at the considered frequency without saturation.

Frequency of the sinusoidal AC supply.

02

Result

Select a target and calculate.

Calculation

Z = √(R² + (2π·f·L)²)

With no capacitor, impedance follows from the geometric sum of resistance and inductive reactance.

Understand the inputs
  • Impedance ZMagnitude of the complex AC impedance of the series circuit.
  • Resistance RResistive part, e.g. choke or motor-winding resistance.
  • Inductance LEffective inductance at the considered frequency without saturation.
  • Frequency fFrequency of the sinusoidal AC supply.
Example

R=10 Ω, L=50 mH and f=50 Hz give XL≈15.71 Ω and Z≈18.62 Ω.

Assumptions and limits

Linear ideal components in sinusoidal steady state with no capacitance in the branch; skin effect, core loss and saturation are excluded.

Technical article

Understand RL series circuit impedance

This calculator determines the impedance of a series resistor-inductor circuit with no capacitor, the most common practical case of a choke or motor winding on an AC supply.

What does this quantity describe?

For a series R-L circuit, resistance and reactance add geometrically: Z=√(R²+XL²) with XL=2π·f·L.

Formula and variables

Z = √(R² + (2π·f·L)²)

  • Z = √(R² + (2π·f·L)²)
  • XL = 2π·f·L
Symbol / inputMeaning
Impedance ZMagnitude of the complex AC impedance of the series circuit.
Resistance RResistive part, e.g. choke or motor-winding resistance.
Inductance LEffective inductance at the considered frequency without saturation.
Frequency fFrequency of the sinusoidal AC supply.

Choose the inputs correctly

R is the resistive winding resistance, L the effective inductance and f the mains or operating frequency.

How to use the calculator

Take R from a DC measurement, L from a datasheet or bridge measurement, and use the actual operating frequency.

Worked example

R=10 Ω, L=50 mH and f=50 Hz give XL≈15.71 Ω and Z≈18.62 Ω.

Understand the result and units

At low frequencies R dominates; at high frequencies XL dominates impedance.

R and Z are resistances, L an inductance and f a frequency.

Useful next calculation

With added capacitance, RLC series-circuit current gives the complete case.

Typical applications

Estimating inrush current of chokes and motor windings on AC supply, and a preliminary step before a full RLC calculation when no capacitor is present.

Assumptions, limits and common mistakes

Linear ideal components in sinusoidal steady state with no capacitance in the branch; skin effect, core loss, saturation and harmonics are excluded.

Common mistake: Do not misuse the existing RLC calculator with C=0; this calculator is more direct and clear for the pure RL case.

Frequently asked questions

What is “RL series circuit impedance” used for?

Estimating inrush current of chokes and motor windings on AC supply, and a preliminary step before a full RLC calculation when no capacitor is present.

Where do the input values come from?

R is the resistive winding resistance, L the effective inductance and f the mains or operating frequency.

What does the result not cover?

Linear ideal components in sinusoidal steady state with no capacitance in the branch; skin effect, core loss, saturation and harmonics are excluded.

Sources, method and review

  • Rudolf Busch, Elektrotechnik und Elektronik für Maschinenbauer und Verfahrenstechniker, 4th ed. 2006, Abschnitt 5.8.1 Komplexer Widerstand; Buchbeispiel R = 10 Ω, L = 64 mH, 50 Hz → Z = 22,4 Ω, φ = 63,4° (local chapter PDF)

Our method, source hierarchy and automated checks are documented on the methodology page. Read the methodology

Responsible
NormCalc-Redaktion
Last updated
2026-09-16