NormCalcEngineering tools
P = Q/t

Heating power from heat and time

Shorter heating time requires proportionally more power.

MINTSI
01

Inputs

Thermal load power before system losses.

Required sensible energy.

Time to reach target temperature change.

02

Result

Select a target and calculate.

Calculation

P = m·c·ΔT/t

Shorter heating time requires proportionally more power.

Understand the inputs
  • Average heating power P — Thermal load power before system losses.
  • Heat quantity Q — Required sensible energy.
  • Heating time t — Time to reach target temperature change.
Example

418.6 kJ in 100 s equals 4.186 kW.

Assumptions and limits

Constant average power; heat losses are omitted.

Sources
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